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3 years ago

The absolute value of 4+7i is equal to the square root of?

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

Of 3.............................................

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Write each points position as an ordered pair, like (1,2). A: B: C: D:

schepotkina [342]

Answer:

A: (-7, 4)

B: (-6, -4)

C: (0, -3)

D: (2, 0)

Step-by-step explanation:

The first number in an ordered pair is the x point, so which number the point aligns with on the horizontal line.

The second number in an ordered pair is the y point, so which number the point aligns with on the vertical line.

If you look at point B you can see that it is directly below the -6 on the horizontal line and directly left of the -4 on the vertical line.

This means that point B is at (-6, 4)

Please give brainliest if I helped! :)

4 0

2 years ago

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CAN SOMEONE PLEASE HELP ME WITH THISS WITH THE LAST TWO QUESTION PLEASE

diamong [38]

C. $340 you would add the money up and then subtract both checks he wrote which is $341 and the nearest 10 would be $340
D. $500 the same step as the last but don’t subtract friday which would be $497 and the closest 10 is $500

8 0

3 years ago

What is the formula to find distance in coordinate geometry, given coordinates (x_1, y_1), (x_2, y_2)? (valid variables for this

madreJ [45]

Answer:

The distance formula is: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Given:

Two points on a coordinate plane are given as:

$(x_1,y_1)\ and\ (x_2,y_2)$

Now, let the points be $A(x_1,y_1)\ and\ B(x_2,y_2)$ and let 'd' be the distance between the two points.

Now, join the points A and B to make a line segment AB.

Also, draw a right angled triangle ABC right angled at point C. Point C is is the intersection of horizontal and vertical lines drawn from points A and B respectively as shown in the figure below.

From the triangle ABC, we observe that:

AB = $d$

AC = $x_2-x_1$

BC = $y_2-y_1$

Now, we use Pythagoras theorem to find 'd'. This gives,

$AB^2=AC^2+BC^2\\\\d^2=(x_2-x_1)^2+(y_2-y_1)^2$

Now, taking square root on both sides, we get:

$\sqrt{d^2}=\pm\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Ignoring the negative result as distance can never be negative.

Therefore, the formula to find distance in coordinate geometry, given coordinates $(x_1, y_1), (x_2, y_2)$ is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

4 0

3 years ago

A recipe requires 3/4 cups of nuts for 1 cake. Enter the maximum number of cakes that can be made using 7 1/2 cups of nuts

nirvana33 [79]

10 cakes can be made

Explanation:
Convert 7 1/2 to an improper fraction
15/2 divided by 3/4
Flip the second fraction and multiply instead of divide
15/2 x 4/3
multiply the tops: 15 x 4 = 60
Over the bottoms multiplied together 2x3=6
60/6=10
therefore 10 cakes can be made

5 0

3 years ago

Evaluate (343^-1/4)^-4/3

Sliva [168]

Answer:

Step-by-step explanation:

pictomath lol

5 0

3 years ago

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