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seraphim [82]
3 years ago
10

Measurements show that the ph of a particular lake is 4.0. What is the hydroxide ion concentration of the lake?

Chemistry
1 answer:
Natasha2012 [34]3 years ago
3 0

Answer:

[OH⁻] → 1×10⁻¹⁰

Explanation:

pH = - log [H⁺]

pOH = - log [OH⁻]

pH + pOH = 14

4 + pOH = 14

14 - 4 = 10 → pOH

10^-pOH = [OH⁻]

10⁻¹⁰ = [OH⁻] → 1×10⁻¹⁰

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Answer:

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3 years ago
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3 years ago
I need help on both a and b of question 1
marishachu [46]

Answer:

(a) -0.00017 M/s;

(b) 0.00034 M/s

Explanation:

(a) Rate of a reaction is defined as change in molarity in a unit time, that is:

r = \frac{\Delta c}{\Delta t}

Given the following reaction:

2 N_2O_5 (g)\rightleftharpoons 4 NO_2 (g) + O_2 (g)

We may write the rate expression in terms of reactants firstly. Since reactants are decreasing in molarity, we're adding a negative sign. Similarly, if we wish to look at the overall reaction rate, we need to divide by stoichiometric coefficients:

r = -\frac{\Delta [N_2O_5]}{2 \Delta t}

Reaction rate is also equal to the rate of formation of products divided by their coefficients:

r = \frac{\Delta [NO_2]}{4 \Delta t} = \frac{\Delta [O_2]}{\Delta t}

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r_{N_2O_5} = \frac{0.066 M - 0.100 M}{200.00 s - 0.00 s} = -0.00017 M/s

(b) Using the relationship derived previously, we know that:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

Rate of appearance of nitrogen dioxide is given by:

r_{NO_2} = \frac{\Delta [NO_2]}{\Delta t}

Which is obtained from the equation:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

If we multiply both sides by 4, that is:

-\frac{4 \Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{\Delta t}

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If there are two similar, oxygen-containing ions, the ion with more oxygen atoms ends in
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<span>there is no answer so i think it should be  -ate. not sure tho without the options

</span>
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