Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
92% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Because of the -2 at the end of the function, we know it is shifted down. The +1 means it is shifted left. The answer is the last graph (the one with a y-intercept of -1).
Answer: 80 miles for the first ship, and 150 miles for the other.
Explanation:
First thing we should do is correspond each number with a letter:
Let x be the distance travel by ship heading east
Let y be the distance travel by ship heading south
y = x + 70 -- (1)
sqrt(x^2 + y^2) = 170 -- (2)
Subtract (1) into (2):
sqrt(x^2 + (x + 70)^2) = 170
x^2 + x^2 + 140x + 4900 = 28900
2x^2 + 140x - 24000 = 0
x ^2 + 70x - 12000 = 0
(x - 80)(x + 150) = 0
x = 80 or -150
Since the distance for the first ship can’t be negative, therefore, x = 80 -- (3)
Subtract (3) into (1), therefore, y = 150
Hope this helps! :)
