What is the value of y

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Well y is a varible so dependimg on the equation y can equal many numbers

You might be interested in

PLEASeeeee helppp.Anyone someon

jolli1 [7]

Answer:

32 (degrees)

Step-by-step explanation:

Triangles AED and ACB share a common angle A.

Two of the corresponding sides have the same ratio: AB=AD+DB=2AD, AC=AE+EC=2AE

Therefore the triangles are similar.

Therefore the corresponding angles are congruent, in particular

∠AED ≅ ∠ACB

∠ECF is just another name for ∠ACB

∠AED ≅ ∠ECF

So their measures must be the same,

m∠AED = m∠ECF = 32°

6 0

3 years ago

Please help me solve this

NikAS [45]

Answer:

uhhhhhhhhhhhhhhhhh

Step-by-step explanation:

i wish i knew

6 0

3 years ago

the sum of the internal angles of a regular polygon is equivalent to 56 right angles. Find the measure of the central angle of t

kykrilka [37]

If x is the number of sides of the regular polygon, then the sum of the interior angles is (x - 2) * 180 = 56 * 90. Solving for x gives 30 for the number of sides of the regular polygon.

To get the central angles measure, divide 360 by 30 to get 12 degrees for the measure of one of the 30 central angles.

Answer: 12 degrees

7 0

3 years ago

A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache

trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1 be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

$H_{0}$ : p2=p1

$H_{a}$ : p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of high school teachers who were single ( $\frac{36}{180} =0.2$ )
p is the proportion of elementary teachers who were single ( $\frac{15}{100} =0.15$ )