What is the value of y

Carter's football team played 10 games this season. They won only 20% of their games. How many games did Carter's team lose?

Fynjy0 [20]

The answer is eight (8)

7 0

3 years ago

If 36 is 90% of a value, what is that value?

laila [671]

You know 36 is 90% of a value, so it will equal 90/100.
Multiply 90/100 types x (value). Easiest way is to simplify 90/100 = 9/10.
x = 36 / 9/10
x = 360 / 9
x = 40
Therefore, the value would be 40.

4 0

3 years ago

Read 2 more answers

Bill buys and sells laptops. Last month Bill bought 50 laptops. He paid £400 for each laptop. He sold 40 of these laptops at a p

Ivenika [448]

Answer:

As Bill's sales is £25400, which is greater than £25000, he achieved his target.

Step-by-step explanation:

Cost of each laptop = £400

lets calculate for 40 laptops first

Given, he sold 40 of these at 30% profit

30% of cost price = 30% of £400 = 30/100 * 400 = 120

Therefore, selling price of these laptops = £400 + £120 = £520

Total sales generated from selling 40 of these laptop = 40*£520

= £520 =£20,800

lets calculate for 10 laptops now

Given, he sold 10 of these at 15% profit

15% of cost price = 15% of £400 = 15/100 * 400 = 60

Therefore, selling price of these laptops = £400 + £60 = £460

Total sales generated from selling 10 of these laptop = 10*£460

= £4600

Total sales generated from selling all the 50 laptop =

Total sales generated from selling 40 of these laptop + Total, sales generated from selling 10 of these laptop = £20,800 + £4600 = £25,400

Target for Bill = £25000

As his sales is £25400, which is greater than £25000, he achieved his target.

6 0

3 years ago

Example of when you would use the friendly numbers strategy to subtract

Yuliya22 [10]

Really big numbers that can easily be estimated.
like
9,998 - 2,999

4 0

3 years ago

According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets

Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

Assumptions:

The sample size (n) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean p and standard deviation $\sqrt{\frac{p(1-p)}{n} }$ .

Since the sampling distribution of sample proportions follows a normal distribution use the z-test for one proportion to perform the test.

The hypothesis is:

$H_{0}$ : The proportion of U.S. households that owned two or more televisions is 83%, i.e. $p=0.83$

$H_{1}$ :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. $p< 0.83$

Decision Rule:

At the level of significance α = 0.05 the critical region for a one-tailed z-test is:

$\\ Z\leq -1.645\\$

**Use the z table for the critical values.

So, if $\\ Z\leq -1.645\\$ the null hypothesis will be rejected.

Test statistic value:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

Here $\hat{p}$ is the sample proportion.

Compute the value of $\hat{p}$ as follows:

$\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80$

Now compute the value of the test statistic as follows:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383$

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

Conclusion:

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is 83%.

6 0

3 years ago