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Drupady [299]
3 years ago
8

What is the answer to this sum y(y+6y2

Mathematics
1 answer:
Nataliya [291]3 years ago
6 0
Y (y + 6y^2) = y^2 + 6y^3
You might be interested in
Use cross products to find the area of the triangle in the xy-plane defined by (1, 2), (3, 4), and (−7, 7).
Free_Kalibri [48]

I love these. It's often called the Shoelace Formula. It actually works for the area of any 2D polygon.


We can derive it by first imagining our triangle in the first quadrant, one vertex at the origin, one at (a,b), one at (c,d), with (0,0),(a,b),(c,d) in counterclockwise order.


Our triangle is inscribed in the a \times d rectangle. There are three right triangles in that rectangle that aren't part of our triangle. When we subtract the area of the right triangles from the area of the rectangle we're left with the area S of our triangle.


S = ad - \frac 1 2 ab -  \frac 1 2 cd - \frac 1 2 (a-c)(d-b) = \frac 1 2(2 ad - ab -cd - ad +ab +cd -bc) = \frac 1 2(ad -bc)


That's the cross product in the purest form. When we're away from the origin, a arbitrary triangle with vertices A(x_1, y_1), B(x_2, y_2), C(x_3, y_3) will have the same area as one whose vertex C is translated to the origin.


We set a=x_1 - x_3, b= y_1  - y_3, c=x_2 - x_3, d=y_2- y_3


S= ad-bc=(x_1 - x_3)(y_2 - y_3) -(x_2-x_3)(y_1 - y_3)


That's a perfectly useful formula right there. But it's usually multiplied out:


S= x_1y_2 - x_1 y_3  - x_3y_2 + x_3 y_3 - x_2 y_1 + x_2y_3 + x_3 y_1 - x_3 y_3


S= x_1 y_2 - x_2 y_1  + x_2y_3 - x_3y_2   + x_3 y_1 - x_1 y_3


That's the usual form, the sum of cross products. Let's line up our numbers to make it easier.


(1, 2), (3, 4), (−7, 7)

(−7, 7),(1, 2), (3, 4),


[tex]A = \frac 1 2 ( 1(7)-2(-7) + 3(2)-4(1) + -7(4) - (7)(3)

8 0
4 years ago
Lily is going for a run. she runs at a speed of 4 miles per hour for 6.4
Nezavi [6.7K]

Answer:

She runs for 1.6 hours

Step-by-step explanation:

For this, one way to do it is to just set 1 hour over 4 miles equal to x hours for 6.4 miles. The reason this is done is because if the speed is constant that means the rate stays the same, which means the ratio of miles to hours should always be the same, so the two ratios must be equivalent.

1/4 = x/6.4

Multiply both sides by 6.4 to get x by itself:

6.4/4 = x

1.6 = x

Hope that helps!

4 0
4 years ago
How far is the star away from the earth in AU?<br>.000302°<br>1AU​
andrew11 [14]

Answer:

  379,442 AU

Step-by-step explanation:

The angle bisector is the altitude of the triangle. The resulting right triangle has a distance of 1 AU opposite the 0.000151° angle. The length we're interested in is the hypotenuse of the triangle. The relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  Hypotenuse = Opposite/Sin

  E-S distance = (1 AU)/sin(0.000151°) ≈ 379,442 AU

The star is about 379,442 AU from Earth.

6 0
3 years ago
Need help on this didn’t study for it but it’s easy
taurus [48]

Answer:

x * 17.5 = y

Step-by-step explanation:

7 0
3 years ago
Please please do this
notka56 [123]

Answer:

1: 12 and 48

2: 45 and 15

3: 2 and 58

Step-by-step explanation:

60-12=38

60-15=45

60-2= 58

5 0
3 years ago
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