What substance located within the chloroplasts of green plant cells collects light for use in photosynthesis?
1 answer:
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Explanation:
Respiration in the mitochondria utilizes oxygen for the production of ATP in the Krebs’ or Citric acid cycle via the oxidization of pyruvate (through the process of glycolysis in the cytoplasm).
overall: C6H12O6 (glucose) + 6 O2 → 6 CO2 + 6 H2O + ≈38 ATP
Further Explanation:
In all eukaryotic cells, mitochondria are small cellular organelles bound by membranes, these make most of the chemical energy required for powering the biochemical reactions within the cell. This chemical energy is stored within the molecule ATP which is produced.
Oxidative phosphorylation follows; this is a process in which the NADH and FADH2 made in previous steps of respiration process give up electrons in the electron transport chain these are converted it to their previous forms, NADH+ and FAD. Electrons continue to move down the chain the energy they release is used in pumping protons out of the matrix of the mitochondria.
This forms a gradient where there is a differential in the number of protons on either side of the membrane the protons flow or re-enter the matrix through the enzyme ATP synthase, which makes the energy storage molecules of ATP from the reduction of ADP. At the end of the electron transport, three molecules of oxygen accept electrons and protons to form molecules of water...
- Glycolysis: occurs in the cytoplasm. 2 molecules of ATP are used to cleave glucose into 2 pyruvates, 4 ATP and 2 electron carrying NADH molecules. (2 ATP are utilized for a net ATP of 2)
- The Citric acid or Kreb's cycle: in the mitochondrial matrix- 6 molecules of CO2 are produced by combining oxygen and the carbon within pyruvate, 2 ATP oxygen molecules, 8 NADH and 2 FADH2.
- The electron transport chain, ETC: in the inner mitochondrial membrane, 34 ATP, electrons combine with H+ split from 10 NADH, 4 FADH2, renewing the number of electron acceptors and 3 oxygen; this forms 6 H2O, 10 NAD+, 4 FAD.
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Answer:
1
Female gametes:
ab= 0%
ab+=0%
a+b=0%
a+b+=0%
for the miniature phenotype to occur, it is necessary to contain two recessive characters and the female must have both for it to occur, if it is homozygous for b + it will have 2 alleles b +, understanding that the female is aab + b it will only occur gametes ab +
.
2. Phenotype
Miniature body + gray=25%
Large body +gray = 50%
Large body +ebony = 25%
Miniature body +ebony =0%
As the crossing cannot occur in males, the gametes it can produce are: ab + and a + b. Although the crossing can occur in women. The gametes produced are: ab +, a + b, ab and a + b +.
the crossing occurs only in the females generating the gametes ab +, a + b, ab and a + b +
The genotypes corresponding to:
Punnet graphic
large gray body: a + ab + b, a + ab + b +, a + a + b + b
big body and ebony: a + a + bb, a + abb
miniature and gray body: aab + b +, aab + b
