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Dmitry_Shevchenko [17]
3 years ago
13

2- How do ecologists organize the environment?

Biology
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

Ecologists generally organize the biological world in a nested hierarchy. Above the level of the individual organism, from the least to most inclusive, the levels of this hierarchy are the population, community, ecosystem, biome, and biosphere.

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Saco membranoso lleno de fluido
BartSMP [9]

Answer:

La vacuola es el término correcto

(The vacuole is the correct term)

Explanation:

Las vacuolas son burbujas de almacenamiento que se encuentran en las células. Se encuentran tanto en células animales como vegetales, pero son mucho más grandes en células vegetales. Las vacuolas pueden almacenar alimentos o cualquier variedad de nutrientes que una célula pueda necesitar para sobrevivir. Incluso pueden almacenar productos de desecho para proteger el resto de la celda de la contaminación.

(Vacuoles are storage bubbles found in cells. They are found in both animal and plant cells but are much larger in plant cells. Vacuoles might store food or any variety of nutrients a cell might need to survive. They can even store waste products so the rest of the cell is protected from contamination.)

por favor ofrece una brainliest

(please offer a brainliest!)

7 0
3 years ago
Which of the following elements does soil needed in the largest quantities to sustain plant life
beks73 [17]
Nitrogen is the answer :)
3 0
3 years ago
Read 2 more answers
What is the climate of most of central and Eastern Europe
Ainat [17]

B. Mainly humid-continental with cool summers.

Thanks :)

4 0
3 years ago
PLEASE HELP!!!!100 POINTS WILL MARK BRAINLIEST
Juli2301 [7.4K]
It should be an igneous rock because it formed by the volcanoes lava cooling down
7 0
3 years ago
Read 2 more answers
An owl has good night vision because its eyes can detect a light intensity as small as 5.0 × 10-13 W/m2. What is the minimum num
Lady bird [3.3K]

Answer:

Thus, the minimum number of photons per second is 77.34

Explanation:

Light intensity, I_{min} =  5\times 10^{-13} W/m^{2}

Pupil has a diameter, d = 8.5 mm

                                      = 8.5 x 10^{-3} m

Radius of the eye, r = 4.25 x 10^{-3} m

∴ Area of the eye, A = \pi .r^{2}

                                 = 3.14\times \left ( 4.25\times 10^{-3} \right )^{2}

                                = 5.6\times 10^{-5} m^{2}

Let P_{min} be the minimum number of photons.

Therefore, P_{min} = I_{min} x A

                                              = 5\times 10^{-13} x 5.6\times 10^{-5}

                                             = 2.8\times 10^{-17} W

Thus the minimum number of photons is given by

N_{min}=P_{min}/E

where E = hc/\lambda

             = \left (6.63\times 10^{-34}\times 3\times 10^{8}  \right )/548\times 10^{-9}

            = 3.62\times 10^{-19} J

Therefore, N_{min} = \frac{2.8\times 10^{-17}}{3.62\times 10^{-19}}

                                              = 77.34 photons per second

Thus, the minimum number of photons per second is 77.34

4 0
3 years ago
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