2d-7=11d+26
-2d-26=-2d-26
-33/9=9/9d
d= -33/9
d= - 11/3
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Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
x=5
Step-by-step explanation:
Answer: -40
Multiply 2 by 4.
8+4•3-30•2
Multiply 4 by 3
8+12-30•2
Multiply-30 by 2
8+12-60
Simplify by adding and subtracting:
Add 8 and 12
20-60
Subtract 60 from 20
-40
<span>We can calculate the nearest integer of the square root by estimation. </span>
<span>We know that 6*6=36, 7*7=49, 8*8=64, 9*9=72,</span>
<span>So 61 is nearest to 64 and acccording this the square root of 61 to the nearest integer is 8.
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