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3 years ago

What is the surface area of 8ft 3ft 3ft 3ft

Mathematics

1 answer:

Rainbow [258]3 years ago

3 0

Answer:

multiply them all and you will get the answer. use calculator

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3,471 into scientific notation

anzhelika [568]

Answer:

3.471 x 10^3

hope i helped

3 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

What is the center of a circle whose equation is x^2+y^2-12x-2y+12=0

Evgen [1.6K]

Answer:

(6, 1)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

HELP OMG PLEASE ITS EASY IM JUST LAZY TO USE MY BIG BRAIN TY <3

7nadin3 [17]

Answer:

3. <0, <BOA, <ABO

4. <E, <NED,<DEN

here you guess and judge by your basic knowledge of angles and guess the angle measurement. and as far as the angle names with three points there should be three names and so the angle you are measuring must always be in the middle and ya :))

5 0

3 years ago

If Linda scored 83 points, what is Lisa's score?

Zepler [3.9K]

Is it a multiple choice question

8 0

3 years ago