Answer:
a)
b)
Step-by-step explanation:
From the question we are told that
The Function

Generally the differentiation of function f(x) is mathematically solved as


Therefore

Generally critical point is given as



Generally the maximum and minimum x value for critical point is mathematically solved as

Where
Maximum value of x

Minimum value of x

Therefore interval of increase is mathematically given by


Therefore interval of decrease is mathematically given by

Generally the second differentiation of function f(x) is mathematically solved as

Generally the point of inflection is mathematically solved as


Therefore inflection points is given as


a)Generally the concave upward interval X is mathematically given as


b)Generally the concave downward interval Y is mathematically given as

Answer:
1) B
Step-by-step explanation:
1)
The formula for the volume of a prism is h * l * w
So, if we do that we get 25/18
2) B
Lets say we talk the top surface, there are 30 cubes on that surface and we want to find the volume of one cube so we are going to divide by 50. we take the measurements which are 5/6 and 1 for the top surface and we multiply. We get an answer of 5/6 now we divide by 30
So...
5/6 * 1/30 (We switched the numbers around because we are dividing.)
5/6 * 1/30 = 5/180 now we can simplify this to 1/36.
5 and 180 are a factor of 5
Hope this helps
Answer:
Step-by-step explanation:
1

is the answer you're looking for.
Its Gonna be Hours Divided by rooms.