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Morgarella [4.7K]

3 years ago

14

Can you please answers this question for me?( the top one with 65/207)

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

choose a random number that isn't 12 (like 23) and multiply it by 3, then add 12. Then set up the division problem you have to generate with that new number as the number being divided, and the number you first chose as the number you are dividing it by. You should have a division problem that solves to equal 3 with a remainder of 12.

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Create an example of a irrational value between 2 and 3

jonny [76]

Answer:

the number of irrational numbers between 2 and 3 are √5, √6, √7, and √8,

Step-by-step explanation:

these are not perfect squares and cannot be simplified further.

#HopeIthelps

5 0

3 years ago

The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?

Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know:

The initial quantity of silicone-32 is 30 g.
The time elapsed is 300 years.
The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

$N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g$

22.38 g of silicone-32 will be present in 300 years.

7 0

3 years ago

The Junior Beta club needs to raise $1513.75 to go to a national convention. If they decided to sell candy bars at $1.25 each, h

rusak2 [61]

Answer:

1,211 candy bars.

Step-by-step explanation:

You divide the goal by how much the bars are selling for, or 1513.75/1.25. The answer to this is 1,211 candy bars.

4 0

4 years ago

Read 2 more answers

What is the answer to 8x^3+125 by factoring the perfect cube?

expeople1 [14]

Answer:

$\large\boxed{8x^3+125=(2x+5)(4x^2-10x+25)}$

Step-by-step explanation:

$8x^3+125=2^3x^3+5^3=(2x)^3+5^3\\\\\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+5)((2x)^2-(2x)(5)+5^2)\\\\=(2x+5)(4x^2-10x+25)$

3 0

4 years ago

Please help math thank you

Alina [70]

a: 30

b:40

c:78

d:36

e:20

f:96

5 0

4 years ago

Read 2 more answers