1) 6, 18, 54
2) 5/3, 14/9, 41/27
3) 1.5, 2.5, 2.5
Step-by-step explanation:
1)
The function that we have in this problem is

We want to find the first 3 iterations.
The initial value is:
x = 2
To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

Finally, the 3rd iteraction is given by:

2)
Here in this problem the function that we have to use is

The initial value is

So the first iteration is given by

To find the 2nd iteration, we substitute this value into g(x) again:

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

3)
The function in this problem is

The initial value is
x = 0.5
So, the first iteration is:

The second iteration is given by

Finally, the 3rd iteration is
