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3 years ago

Find the value of x in the isosceles triangle shown below.

Mathematics

1 answer:

Vika [28.1K]3 years ago

5 0

Answer:

x = √40

(Option B)

Step-by-step explanation:

Focus on one half of the triangle.

Base of half triangle

= 4÷2

= 2

Applying Pythagoras' Theorem,

x² = 6² +2²

x² = 40

x = √40

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3 years ago

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marin [14]

m x H = $\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]$

Step-by-step explanation:

Step 1; Multiply 5 with this matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get a matrix $\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]$

Multiply the fraction $\frac{2}{5}$ with the matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get $\left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]$

Step2; Now equate corresponding values of the matrices with each other.

-5 = $\frac{-2m}{5}$ and so on. By equating we get the value of m as $\frac{25}{2}$

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get $\left[\begin{array}{ccc}2&9&-9\\\end{array}\right]$ .

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

$\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]$ . Equating the matrices from step 3 and 4 we get the value of H as $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 5; Now to find the value of m x H we need to multiply the value of $\frac{25}{2}$ with the matrix $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 6; Multiplying we get the matrix m x H = [ -25 $\frac{75}{2}$ $\frac{-25}{2}$ ]

8 0

3 years ago

What is the value for x? Enter your answer in the box. x =

BaLLatris [955]

<A = <C = 73
<B = 180 - (<A + C)
6x + 4 = 180 - 2(73)
6x + 4 = 180 - 146
6x + 4 = 34
6x = 30
x = 5

answer
x = 5

6 0

3 years ago

Find the value of x in the isosceles triangle shown below.​

Find the value of x in the isosceles triangle shown below.