The total amount that your friend spent is the sum of the cost for 3 bags of wild bird seed and the bird feeder. By letting x be the cost of each bag of wild bird seed, the total cost for purchasing 3 bags of this is 3x. The equation that may be used to determine x is letter "B. 3x + 18 = 45". Each bag costs $9.
Answer:
Sakura spoke for 2 minutes in Hungarian and for 3 minutes in Polish
Step-by-step explanation:
So make the variables.
Hungarian = x
Polish = y
x and y are the amount of time she spent in minutes.
x + y = 5
150x + 270 = 190y
x = 5 - y
750 - 150y + 270 = 190y
1020 = 340y
y = 3
x = 2
<span>A quarter is equivalent to 25 cents or $0.25 and a nickel is equal to 5 cents or $0.05. In the given in this item, if there are x nickels then, there are x + 7 quarters. With these and the total amount known, we can now compute for the value of x.
(x)(0.05) + (x + 7)(0.25) = 2.65
Simplifying,
0.05x + 0.25x + 1.75 = 2.65
Simplifying further,
0.3x = 0.9
The value of x from the equation is 3. Hence, there are 10 quarters.</span>
Answer:
x=−32/5
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
1/2(1/4x−3/5)=1/4(2/5+3/4x)
(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)
1/8x+−3/10=1/10+3/16x
1/8x+−3/10=3/16x+1/10
Step 2: Subtract 3/16x from both sides.
1/8x+−3/10−3/16x=3/16x+1/10−3/16x
−1/16x+−3/10=1/10
Step 3: Add 3/10 to both sides.
−1/16x+−3/10+3/10=1/10+3/10
−1/16x=2/5
Step 4: Multiply both sides by 16/(-1).
(16/−1)*(−1/16x)=(16/−1)*(2/5)
x=−3/25
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
