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Debora [2.8K]
3 years ago
12

URGENT HELP ASAP

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

(2x - 1)

Step-by-step explanation:

  • <em>Volume of a rectangular prism is: V = lwh, where l= lenght, w= width, h= height</em>
<h3>Given</h3>
  • V = 36x³ + 60x² + x - 20
  • l = (3x + 4)
  • w = (6x + 5)

and

  • h = ?
<h3>Solution</h3>

Since the volume is the polynomial of third degree and the two of the factors are of the first degree, the third factor is going to be a first degree  as well in the format of (mx +n)

<u>So we have below equation:</u>

  • 36x³ + 60x² + x - 20 = (3x + 4)(6x + 5) (mx + n)

<u>We can work out the value of m and n:</u>

  • 3x*6x*mx = 36x³
  • 18mx³ = 36 x³
  • m = 2

<u>And</u>

  • 4*5*n = -20
  • 20n = -20
  • n = -1

So we get the factor of (mx + n) = (2x - 1)

<u>Therefore </u>

  • h = (2x - 1)

<u>Proof of the polynimial is correct:</u>

  • (3x + 4)(6x +5)(2x - 1) =
  • (18x²+39x+20)(2x - 1) =
  • 36x³ - 18x² + 78x² - 39x + 40x - 20 =
  • 36x² + 60x² + x - 20

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Read 2 more answers
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

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Can some one help me asap
zavuch27 [327]
It'd be easier to do #18 if y ou were to break it up:

                                                        14* (first term + 14th term)
Sum from n=1 to 14 of n =  S      = ---------------------------------
                                               14                       2
                                    
     14(1+14)
= ---------------- = 7(15) = 105 
           2

The sum of twice that is 210.  The sum of "1 from n=1 to n=14" is just 14.

The final sum is 210 + 14 = 224 (answer)
4 0
3 years ago
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