Assuming we need to find i such that
1 ≤ i ≤ n and t[i]=i.
If we need to find only the first occurrence, we can do:
for i:1 to n {
if t[i]=i then return(i)
}
If exhaustive search is required, then put the results (values of i) in an array or a linked list, return the number of values found, and the array (or linked list).
Answer:
D
Step-by-step explanation:
6.60/6
= x/3
then u can cross multiply
Answer:
Step-by-step explanation:
242=b+49
Answer: y=7, x=2
Step-by-step explanation:
∠Q+∠P=180° (∠s between 2 // lines)
97°+(12y-1)°=180°
12y-1=83°
12y=84
y=7
5x+6=8x (Iso triangle)
x=2
Answer:
There are two real and different roots
Step-by-step explanation:
The discriminant is given by b²-4ac
(-12)²-4(70×1)
144-280
136
Now 136>0
