Answer:
f(-10) = 1,100
Step-by-step explanation:
f(-10) = (-10)^2 - (-10)^3
= 100 - (-1000)
= 1,100
Answer:
a = 49°
Step-by-step explanation:
OB = OC ( both radii of the circle ), thus
Δ BOC is isosceles and the base angles are congruent, that is
∠ OBC = ∠ OCB = 41° , so
∠ BOC = 180° - (2 × 41)° = 180° - 82° = 98°
The angle on the circumference BAC is half the angle at the centre for angles subtended on the same arc , thus
a = 0.5 × 98° = 49°
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
Answer:
? = 74.64111442
Step-by-step explanation:
=
=
*27
=
(27/28)
=74.64111442
