3.25(4)+2(6) --plug in values
13+12 --multiply
$25 --answer
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
Learn more about Sequences on:
brainly.com/question/12246947
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7+10x-2x-2=-3
—-Combine like terms...10x-2x=8x and 7-2=5
8x+5=-3
——subtract 5 on both sides.. the 5’s will cancel each other and -3-5=-8
8x=-8
——Divide 8 on both sides...the 8’s will cancel out and -8 divided by 8 = -1
Answer: x = -1
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x
Answer:
Answer:
Skateboarder B will have traveled 1,680 feet farther.
Step-by-step
Possible reasoning: There are 240 seconds in 4 minutes
