What is the slope of the the line that goes through (4,3) and (8,5)
1 answer:
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Answer:
a = 2, b = - 5
Step-by-step explanation:
Given
y = ax² + bx
is the measure of the slope at x = a
Differentiate each term with respect to x using the power rule
(a
) = na
= 2ax + b, hence
2ax + b = 3 at (2, - 2)
Substitute x = 2 into
4a + b = 3 → (1) and substitute x = 2 into y
4a + 2b = - 2 → (2)
Subtract ( 1) from (2)
b = - 2 - 3 = - 5
Substitute b = - 5 into (1)
4a - 5 = 3 ( add 5 to both sides )
4a = 8 ( divide both sides by 4 )
a = 2
Hi there!
We are given:
cos(7x)cos(4x) = -1 - sin(7x)sin(4x)
Begin by moving all terms with variables to one side:
cos(7x)cos(4x) + sin(7x)sin(4x) = -1
The corresponding trig identity is cos(A - B). Thus:
cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1
cos(3x) = -1
cos = -1 at π, so:
3x = π
x = π/3
We can also find another solution. Let 3π = -1:
3x = 3π
x = π
Thus, solutions on [0, 2π) are π/3 and π.