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Stels [109]
3 years ago
15

Which polynomial is written in standard form for the polynomial below? -7x^2-x^3+x^5+2

Mathematics
1 answer:
mylen [45]3 years ago
7 0
-84-x I hope this helped you and answered your question.
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Write a polynomial function f of least degree that has a leading coefficient of 1 and the given zeros -4,-2,5. write the functio
OLga [1]

Answer:

Step-by-step explanation:

This is a third degree polynomial since we have 3 zeros.  We find these zeros by factoring the given polynomial.  The zeros of a polynomial are where the graph of the function goes through the x-axis (where y = 0).  If x = -4, the factor that gives us this value is (x + 4) = 0 and solving that for x, we get x = -4.  If x = -2, the factor that gives us that value is (x + 2) = 0 and solving that for x, we get x = -2.  Same for the 5.  The way we find the polynomial that gave us these zeros is to go backwards from the factors and FOIL them out.  That means that we need to find the product of

(x + 4)(x + 2)(x - 5).  Do the first 2 terms, then multiply in the third.

(x+4)(x+2)=x^2+2x+4x+8, which simplifies to

x^2+6x+8

No we multiply in the final factor of (x - 5):

(x^2+6x+8)(x-5)=x^3+6x^2+8x-5x^2-30x-40 which simplifies to

f(x)=x^3+x^2-22x-40

If you are aware of the method for factoring higher degree polymomials, which is to use the Rational Root Theorem and synthetic division, you will see that this factors to x = -4, -2, 5.  If you know how to use your calculator, you will find the same zeros in your solving polynomials function in your apps.

3 0
3 years ago
A cereal box has dimensions of 10 1/2 inches by 7 1/2 inches by 2 1/2 inches. What is the volume of the cereal box? 19 1/2 in³ 2
Temka [501]
196 3/8 in^3. To get this, multiply all the numbers together. To find volume, the equation is length x width x height.
5 0
3 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
GEOMETRY find the angle of PRQ NO LINKS!!
anzhelika [568]

Answer:

55

Step-by-step explanation:

Remark

This is a really good question to know the answer to. <PRQ = 1/2 POQ (the central angle. )

The central angle for this question is 110o. So any angle that has its vertex on the circumference is 1/2 110 = 55. The central angle and the angle on the circumference must be related as they are as this question is. (Both are on the same side of PQ which is not drawn but you can draw it).

4 0
3 years ago
The actual length of c in the triangle shown is 15 cm.
Strike441 [17]
The answer is B. Hope this helps!
4 0
3 years ago
Read 2 more answers
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