In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11

Question

docker41 [41]

4 years ago

11

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11

feet long? x (to the nearest tenth) =

Mathematics

2 answers:

vivado [14] · Answer 1 · 2022-01-01T13:45:33+03:00

Answer:

$x=6.11 feet$

Step-by-step explanation:

Given that in a fulcrum weights are perfectly balanced.

One side 40 lb weight is there and another side 50 lb weight is given

Let x be the length of 40 lb weight from fulcrum. Then 50 lbs is at a distance of 11-x.

Then we have since weights are perfectly balanced

$40x = 50(11-x)\\90x=550\\x=6.111$

Thus we get $x=6.11$ feet

Dennis_Churaev [7] · Answer 2 · 2022-01-01T11:33:31+03:00

Dennis_Churaev [7]4 years ago

3 0

The complete question in the attached figure

we know that
if <span>the weights are perfectly balanced
40*(x)=50*(11-x)
40x=550-50x------------> 50x+40x=550--------------> x=6.11

x=6.1 ft

the answer is 6.1 ft</span>