Answer:
y = 5/2x -15
Step-by-step explanation:
5x - 2y = 30
-2y = -5x + 30
y = x -15
In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11
feet long? x (to the nearest tenth) =
2 answers:
Answer:
Step-by-step explanation:
Given that in a fulcrum weights are perfectly balanced.
One side 40 lb weight is there and another side 50 lb weight is given
Let x be the length of 40 lb weight from fulcrum. Then 50 lbs is at a distance of 11-x.
Then we have since weights are perfectly balanced
Thus we get feet
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Answer:
Increasing on it's domain because the slope is positive.
The domain and range are both all real numbers, also known as
.
Step-by-step explanation:
All domain really means is what numbers can you plug in and you get number back from your function.
I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.
The domain is all real numbers.
In interval notation that is .
Now the range is the set of numbers that get hit by y=3x+2.
Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.
If slope is positive, then the line is increasing.
If slope is negative, then the line is decreasing.
So y=3x+2 hits all values of y because it is increasing forever. The range is all real numbers. In interval notation that is .
Answer:
On a unit circle, the point that corresponds to an angle of is at position
.
The point that corresponds to an angle of is at position
.
Step-by-step explanation:
On a cartesian plane, a unit circle is
- a circle of radius
,
- centered at the origin
.
The circle crosses the x- and y-axis at four points:
,
,
, and
.
Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.
When the angle is equal to , the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be
.
To locate the point with a angle, rotate the
segment counter-clockwise by
. The segment would land on the positive y-axis. In other words, the
-point would be at the intersection of the positive y-axis and the circle. Its coordinates would be
.
