In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11
feet long? x (to the nearest tenth) =
2 answers:
Answer:

Step-by-step explanation:
Given that in a fulcrum weights are perfectly balanced.
One side 40 lb weight is there and another side 50 lb weight is given
Let x be the length of 40 lb weight from fulcrum. Then 50 lbs is at a distance of 11-x.
Then we have since weights are perfectly balanced

Thus we get
feet
The complete question in the attached figure
we know that
if <span>the weights are perfectly balanced
40*(x)=50*(11-x)
40x=550-50x------------> 50x+40x=550--------------> x=6.11
x=6.1 ft
the answer is 6.1 ft</span>
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Step-by-step explanation:
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the range is the interval--------> ![[-3,3]](https://tex.z-dn.net/?f=%5B-3%2C3%5D)
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Step-by-step explanation:
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