Answer:
1. 6+(-3)
2. 6+3
3. -6+(-3)
4. -6+3
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Answer:
A, B, C and D. are solutions.
Step-by-step explanation:
x^2 + y^2 = 13
x^2 - y^2 = 5
Check which roots fit the original equations:
If x = 3, A gives
9 + y^2 = 13 giving y = +/- √4 = 2 or -2.
Now plug in x = 3 and y = 2 in the second equation:
9 - (2)^2 = 5
Therefore (3,2) is a solution of the 2 equations.
Following the same procedure for B, C and D:
B. Substituting x = 3 and x = -2 fits both equations so (3, -2) is a solution.
The same is true for C and D.
Answer:Use fraction
Put the number that u want to divide on the numerator and the number that divide the number on the demominator
A variable is a letter, for example x, y or z, that represents an unspecified number.
6 + x = 12
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12.
