1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly_w [17]
3 years ago
8

The base of a triangular sign exceeds the height by 8 inches. If the area of the sign is 24 square inches, find the length of th

e base and the height of the triangle.
Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0
Answer:
_______________________________________________
The height is:  "4 inches" ;
 and the base length is:  "12 inches" .
____________________________________
Explanation:
____________________________________
The formula of the area of a triangle is:

Area = (1/2) * (base length) * (perpendicular height) ; or write as:

A = (1/2) * (b) * (h) ;
_________________________________
 Given:  A = 24 in² ;
              b = h + 8 ;
________________________
 Find:  "b" ;  and:  "h" ;
_____________________________
 →  Since:  " A = (1/2) * b * h " ; 

     →  Plug in our known values:
     
            →  24 = (1/2) * (h + 8) * h ;
_________________________________
Find:  h ;
Find  "b" , which is: "(h +8)" ;
_________________________________
We have:  

  →  24 = (1/2) * (h + 8) * h ;

Multiply EACH SIDE of the equation by "2" ; to get rid of the fraction:
_______________________________________________________
  → 2 * {24 = (1/2) * (h + 8) * h} ;
 
     → to get:
______________________________
     → 48 = 1 * (h + 8) * h ;

↔ Rewrite:  h(h + 8) = 48 ;
_________________________________________
Note the "distributive property of multiplication":
_________________________________________
    a(b+c)  = ab + ac ;
  
    a(b−c)  = ab − ac ;
_________________________________________
  →  So;  h(h + 8) = h*h  + h*8 = h² +8h = 48 ;
______________________________________
We have:  " h² + 8h = 48 " ;  To solve for "h" ;  let us see if we can
          write this equation in "quadratic format" ; that is:
_______________________________________________
    " ax² + bx + c = 0 ;  a ≠ 0 ; " ;
_________________________________________
We have:   h² + 8h = 48  ;  Subtract "48" from EACH SIDE of the equation:
_________________________________________
                  h² + 8h − 48 = 48 − 48 ;
_________________________________________
 to get:    h² + 8h − 48 = 0 ;
_________________________________________
Note that is equation IS, in fact, written in "quadratic format" ;
   that is: "ax² + bx + c = 0 ;  a ≠ 0 " ;  
_________________________________________ 
      in which:  a = 1 ;
(Note:  The "implied coefficient" of "1"; since anything multipled by "1" is that same result);
                      b = 8 ;
                      c = - 48;
_____________________________________
Now, let us see if we can solve by factoring; if we cannot, we can use the quadratic equation formula:
_____________________________________
Let us trying factoring:  h² + 8h − 48 = (h+12) (h − 4) = 0 ; 
________________________________________________
Since anything multiplied by "zero" equals "zero" ; 

Then either:  (h+12) = 0 ;  h = -12 ; 
                     (h − 4) = 0 ;  h = 4 ;
________________________________________________ 
So we have two (2) values for "h" ;  "h = 4" , and "h = -12" .

So, which value do we use for "h"?  Since "h" refer to "height"; 
we know that "height" cannot be a "negative value";  so we use: 

"h = 4" .

Now, we are given:  "b = h + 8 = 4 + 8 = 12 "
_______________________________________
So,  h = 4 ; b = 12.
______________________
Now check our work:  "A = (1/2) (b) (h)" ; Given "A = 24" .

24 = (1/2) (12) (4)?  24 = (1/2) * 48 ?  YES!
______________________________________
So, the height is:  "4 inches" ;
 and the base length is:  "12 inches" .
______________________________________ 
You might be interested in
A farmer's land is separated into sections of size
Evgen [1.6K]
I think it's 9.68 but I might be wrong
4 0
3 years ago
How much larger is 0.30 than 0.3
Xelga [282]
They are both equal because in decimals you can add thousands of zeros and it's still equal.
4 0
3 years ago
A salesman earns 30% commission on the merchandise that he sells last month he sold $600 worth of merchandise how much of commis
romanna [79]

Answer:

$180

Step-by-step explanation:

.3 * 600

5 0
2 years ago
Read 2 more answers
20 for this question needing help
Radda [10]

Step-by-step explanation:

option C is the answer.

hope it helps

7 0
2 years ago
The graph of the function f(x) is shown below.
faust18 [17]
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥

domain is how far the x values go
x is left to right

we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain



range
highest to lowest y value

range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]



Domain=[-3,5)
Range=[-1,3]


B. read above and understand it
5 0
3 years ago
Other questions:
  • Whats the reciprocal<br> of 23
    13·2 answers
  • The graph represents the function f(x) = x2 + 3x + 2.
    10·1 answer
  • Write the equation of a line with slope 3 and y-intercept −3.<br><br> PLS I NEED ASAP
    15·1 answer
  • find the volume of the solid whose base is the region bounded by the x-axis, the curves y=5x, y=3x^2, x=0 and x=1.66667 and whic
    15·1 answer
  • I have more algebra homework its 2 pages
    6·1 answer
  • Average Monthly Temperature Month Temperature January 45 degrees February 42 degrees March 54 degrees April 62 degrees May 78 de
    8·1 answer
  • PLEASEEEE answer!!!! NEED THIS TO GRADUATE
    11·1 answer
  • Which statement is true?
    10·1 answer
  • 2] The band has a ratio of boys to girls of 5 to 4. There are 171 students in the band.
    11·1 answer
  • Solve for the unknown variable "x" in the following linea equation: 2 ( 2x + 20) = 80 X =
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!