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3 years ago

What is the equation of a circle with center (2,-5) and radius 4?

Mathematics

2 answers:

azamat3 years ago

4 0

Answer:

(x - 2)² + (y + k)² = 4²

Step-by-step explanation:

To answer this, we insert the given into (center x-coordinate 2, center y-coordinate -5, radius 4) into the general formula for a circle with center at (h, k) and radius r: (x - h)² + (y - k)² = r² → (x - 2)² + (y + k)² = 4²

Marrrta [24]3 years ago

3 0

The GENERAL equation for EVERY circle with its center at (A, B) and a radius of R is

(x - A)² + (y - B)² = R² .

So if you just stuff in the numbers given in this question, the equation of THIS circle is

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Roger read 4 more books in July then he did in January how many books did he read in July

ivanzaharov [21]

Answer:

Step-by-step explanation:

If he read 9 books in january and read 4 more in july than he did in january then he read 13 books in july.

3 0

3 years ago

What is the answer of a - 5 + -12

Pachacha [2.7K]

-5+-12 is -17
For lack of a better metaphor, it's like digging a pit deeper than it already is.

8 0

3 years ago

Read 2 more answers

Find the surface area and volume of a cylinder with a diameter equal

dangina [55]

Answer:

Volume = 1539.38 cm³

Surface Area = 747.7 cm²

Step-by-step explanation:

Volume = πr² h

V = π(7)²(10)

V = π(49)(10)

V = 490π

V = 1539.38 cm³

Surface Area = 2πrh + 2πr²

SA = 2π(7)(10) + 2π(7)²

SA = 2π(70) + 2π(49)

SA = 140π + 98π

SA = 238π

SA = 747.7 cm²

8 0

2 years ago

Write an equation that expresses the following relationship. p varies jointly with the square of d and the cube of u In your equ

Veronika [31]

Answer:

$p= kd^{2}u^{3}$

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

$p= kd^{2}u^{3}$

5 0

4 years ago

Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3

poizon [28]

The midpoint formula for a segment is:

$x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}$

apply to points R and P

$\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}$

using the definition of slope find the slope of the segment

$m=\frac{y_2-y_1}{x_2-x_1}$

apply to points R and P

$\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}$

to lines are parallel when the slopes are the same

$\mleft\Vert m=1\mright?$

two lines are perpendicular when the product of the slopes is equal to -1

$\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}$

7 0

1 year ago