What is the volume of a cube that measures 0.6 m on each edge?

Mathematics

2 answers:

Licemer1 [7]3 years ago

7 0

Answer:

Volume=a3=0.63=0.216

Tamiku [17]3 years ago

4 0

Volume=a3=0.63=0.216

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Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

Vikki [24]

The equation of the circle: $(x-a)^2+(y-b)^2=r^2$

where:
(a; b) - coordinates of the center
r - a radius

Use: $(a\pm b)^2=a^2\pm2ab+b^2\ \ \ \ (*)$

We have:

$x^2-4x+y^2+8y=-4\\\\x^2-2x\cdot2+y^2+2y\cdot4=-4\ \ \ |add\ 2^2\ and\ 4^2\ to\ both\ sides\\\\\underbrace{x^2-2x\cdot2+2^2}_{(*)}+\underbrace{y^2+2y\cdot4+4^2}_{(*)}=-4+2^2+4^2\\\\(x-2)^2+(y+4)^2=-4+4+16\\\\(x+2)^2+(y-4)^2=16\\\\(x+2)^2+(y-4)^2=4^2$

Answer:
The center: (-2; 4)
The radius: r = 4

7 0

3 years ago

Read 2 more answers

I need help I’m not sure

Daniel [21]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2} \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)$