4 years ago

Hubble's law expresses a relationship between __________.

1 answer:

4 0

The distance of the galaxy and speed at which it is moving away from us

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Marat540 [252]

Answer:

The potential for r > rb is equal to zero.

Explanation:

For r > rb, the potential is:

$V=\frac{Kq}{r}$

Then, the net potential is:

$V_{(r)} =\frac{K(+\epsilon )}{r} +\frac{K(-\epsilon )}{r}$

$K=\frac{1}{4\pi \epsilon _{o} }$

$V_{(r)} =\frac{K(+\epsilon )}{r} -\frac{K(\epsilon )}{r}\\V_{(r)}=0$

8 0

4 years ago

mel-nik [20]

50 c should be right

6 0

3 years ago

slavikrds [6]

Tbh i don’t really know I’m just waiting for y’all to tell me the answer

8 0

3 years ago

elena55 [62]

Answer:

Just find the formula then you can do it

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3 years ago

Zarrin [17]

They do it when they are moving for a while or they are going fast

6 0

3 years ago