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3 years ago

In an inverse relationship when one variable increases the other one____

Physics

1 answer:

slavikrds [6]3 years ago

8 0

Tbh i don’t really know I’m just waiting for y’all to tell me the answer

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A sling psychrometer works because the amount of cooling that occurs in the wet bulb is directly proportional to the ----- of th

ad-work [718]

<u>Temperature of the air</u>

According to sources, the most probable answer to this query is that the wet bulb is directly proportional to the temperature of the air. Thank you for your question. Please don't hesitate to ask in Brainly your queries.

5 0

3 years ago

Use Hooke's Law to determine the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters.

ladessa [460]

Answer:

Work Done = 67.5 J

Explanation:

First we find the value of spring constant (k) using Hooke's Law. Hooke's is formulated as:

F = kx

where,

F = Force Applied = 450 N

k = Spring Constant = ?

x = Stretched Length = 30 cm = 0.3 m

Therefore,

450 N = k(0.3 m)

k = 450 N/0.3 m

k = 1500 N/m

Now, the formula for the work done in stretching the spring is given as:

W = (1/2)kx²

Where,

W = Work done = ?

k = 1500 N/m

x = 70 cm - 40 cm = 0.3 m

Therefore,

W = (1/2)(1500 N/m)(0.3 m)²

3 0

3 years ago

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Korvikt [17]

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} =v_{o} -a*t$

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]

3 0

3 years ago

In a thundercloud there may be electric charges of 45.0 C near the top of the cloud and -45.0 C near the bottom of the cloud. Th

Gala2k [10]

Answer:

The electric force on the top charge is $F=3.44\times 10^6\ N$ .

Explanation:

Given that,

Electric charges in a thundercloud, $q_1=q_2=45\ C$

The distance between charges, d = 2.3 km = 2300 m

Let F is the electric force on the top charge. The electric force is given by the formula as :

$F=\dfrac{kq^2}{d^2}$

$F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}$

$F=3445179.58\ N$

$F=3.44\times 10^6\ N$

So, the electric force on the top charge is $F=3.44\times 10^6\ N$ . Hence, this is the required solution.

7 0

4 years ago

A child squeezes a pillow over his ears during and thunderstorm. Which wave interaction helps decrease the sound of the thunder?

Anastasy [175]

Answer:

Absorption

Explanation:

8 0

3 years ago