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Pavel [41]
3 years ago
12

Anne applies a force on a toy car and makes it move forward. What can be said about the forces acting on the toy car at the mome

nt Anne applies the force? The forces acting on the toy car are .
Options are: applied
balanced
equal
unbalanced
Physics
2 answers:
Mashutka [201]3 years ago
7 0

Answer:

The correct option is "unbalanced forces".

Explanation:

It is given that, Anne applies a force on a toy car and makes it move forward. On the application of force, the car is moving in forward direction. This shows there must be a frictional force acting in opposite direction. Here the forces acting on it are balanced.

If the object does not move at all, then the forces will be balanced. As the forces are equal and opposite in nature . So, they cancel out each other.

So, the correct option is (d) " unbalanced ".

tester [92]3 years ago
5 0

The correct answer to the question is unbalanced .

EXPLANATION:

As per Newton's first laws of motion, we know that a body at rest will be at rest or a body moving with uniform velocity along a straight line will keep on moving with the same velocity along that line unless and until it is compelled by some external unbalanced forces acting on.

Hence, it is the unbalanced force which is responsible for creating the motion on the body.

As per the question, Anne applied some force on the toy car. It is called applied force. There is also frictional force between car and the surface which opposes the motion of the car. The toy car will move due to the net force acting on it. The net force is known as unbalanced force.

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Answer:

The velocity of mass 2m is  v_B = 0.67 m/s

Explanation:

From the question w are told that

     The mass of the billiard ball A is =m

     The initial speed  of the billiard ball A = v_1 =1 m/s

    The mass of the billiard ball B is = 2 m

    The initial speed  of the billiard ball  B = 0

Let the final speed  of the billiard ball A  = v_A

Let The finial speed  of the billiard ball  B = v_B

      According to the law of conservation of Energy

                 \frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

              Substituting values  

                \frac{1}{2} m (1)^2  = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

Multiplying through by \frac{1}{2}m

                1 =v_A^2 + 2 v_B ^2 ---(1)

    According to the law of conservation of Momentum

            mv_1 + 2m(0) = mv_A + 2m v_B

    Substituting values

            m(1)  = mv_A + 2mv_B

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making v_A subject of the equation 2

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Substituting this into equation 1

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