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8090 [49]
3 years ago
11

What would you say to a friend who made this statement, “The visible-light spectrum of the Sun shows weak hydrogen lines and str

ong calcium lines. The Sun must therefore contain more calcium than hydrogen.”?
Physics
1 answer:
Oliga [24]3 years ago
8 0

Explanation:

spectral lines or signatures of elements depend on temperature, the temperature of the sun is about 5800 K.

at this temperature most calcium atoms are excited to higher energy states than hydrogen atoms and this means that calcium atoms are gonna have more signatures than the atoms of hydrogen.

the statement that the sun shows weak hyrogen lines and strong calcium line is wrong because at the sun's temperature most of the hydrogen atoms are in lower energy states while calcium atoms are in higher energy states hence calcium has more or ''strong'' lines than hydrogen.

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A -1.12 μC charge is placed at the center of a conducting spherical shell, and a total charge of +8.65 μC is placed on the shell
Lisa [10]

Answer: 7.53 μC

Explanation: In order to explain this problem  we have to use the gaussian law so we have:

∫E.dS=Qinside/εo we consider a gaussian surface inside the conducting spherical shell so E=0

Q inside= 0 = q+ Qinner surface=0

Q inner surface= 1.12μC so in the outer surface the charge is (8.65-1.12)μC=7.53μC

7 0
3 years ago
Why does a metal spoon left on a bowl of hot soup become warm? A) Metal is a conductor. B) Metal is an insulator. C) Metal produ
mr_godi [17]

A: Metal is a conductor it hold the heat

5 0
3 years ago
Read 2 more answers
Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

4 0
3 years ago
A marble rolls along the floor with a constant velocity of 6 m/s. How far will it have gone after 130 seconds
SCORPION-xisa [38]

Answer:

0.046

Explanation:

displacement = velocity/ time

d = 6m/s / 130s

d = 0.046m

5 0
3 years ago
According to your graph, does the wave speed change with wave length?
fiasKO [112]

Yes

Explanation:

From the graph, we can deduce that the wavelength changes with the speed of the wave.

This is a simple linear graph. A linear graph has a steady gradient and it shows two variables that increases proportionately.

Using the graph, we can establish that as the wavelength of the wave increases the time taken for one wave to pass through increases.

The speed of a wave is given as:

                     V = fλ

   f is the frequency of the wave i.e the number of waves that passes through a point per unit of time

  λ is the wavelength of the wave

The vertical axis on the graph shows the time for 1 wave trip, this is the wave period, T

            f = \frac{1}{T}

Therefore;

    speed of the wave = \frac{λ}{T}

This can be evaluated by solving slope of the graph and finding the inverse.

We can see that as the speed of the wave changes, the wavelength will change.

 

learn more:

Wavelength brainly.com/question/6352445

#learnwithBrainly

3 0
3 years ago
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