4/10 is equal to 2/5 because if you reduce 4/10 you get 2/5 which shows that they are equal.
The greatest comment factor of 28 and 64 is 4.
The factors of 28 are 28, 14, 7, 4, 2, 1.
The factors of 64 are 64, 32, 16, 8, 4, 2, 1.
The common factors of 28 and 64 are 4, 2.
the greatest one of the two factors is 4.
Answer: " 15 % " .
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→ " 12 is <u> 15% </u> of 80 " .
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Step-by-step explanation:
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12 = (n/100) * 80 ;
12 = (80n) /100 ; Solve for "n:
Note: 80/100 = (80/10) / (100/10) = (8/10) = 0.8 ;
12 = (0.8)n ;
↔ (0.8n) = 12
Multiply each side of the equation by "10" ; to get rid of the "decimal" ;
10 * (0.8n) = 10 * 12 ;
to get:
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8n = 120 ;
Divide each side of the equation by "8" ;
to isolate "n" on ONE SIDE of the equation; & to solve for "n" ;
8n/8 = 120/ 8 ;
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to get:
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n = 15 .
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Answer: " 15 % " .
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→ " 12 is <u> 15% </u> of 80 " .
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Hope this helps!
Best wishes!
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Answer:
1)Area; A = ¼πr²
Perimeter; P = πr/2 + 2r
2)A = 19.63 cm²
P = 17.85 cm
3) r = 8.885 cm
4) r = 14 cm
Step-by-step explanation:
This is a quadrant of a circle. Thus;
Area of a circle is πr². A quadrant is a quarter of a circle. Thus;
Formula for Quadrant Area is; A = ¼πr²
A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.
Formula for the quadrant perimeter in the image given is;
P = 2πr/4 + 2r
P = πr/2 + 2r
B) When r is 5 cm;
A = ¼π(5)²
A = 19.63 cm²
P = π(5)/2 + 2(5)
P = 17.85 cm
C) when A is 100cm²:
¼πr² = 100
r² = 100 × 4/π
r² = 78.9358
r = √78.9358
r = 8.885 cm
D) when P = 50 cm.
50 = πr/2 + 2r
50 = (½π + 2)r
r = 50/(½π + 2)
r = 14 cm
