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Answer:
44/100 will be reduced to 11/25
Step-by-step explanation:
Answer:
The speed of the object at time, t=4 is ![20ms^{-1}](https://tex.z-dn.net/?f=20ms%5E%7B-1%7D)
Step-by-step explanation:
The speed is calculated using the formula;
![Speed=\frac{Distance}{Time\:taken}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7BDistance%7D%7BTime%5C%3Ataken%7D)
The distance covered by the object is given in terms of t, as
![s(t)=-2t^2+28t](https://tex.z-dn.net/?f=s%28t%29%3D-2t%5E2%2B28t)
At time t=4, the distance covered by the object is;
![s(4)=-2(4)^2+28(4)](https://tex.z-dn.net/?f=s%284%29%3D-2%284%29%5E2%2B28%284%29)
![s(4)=80m](https://tex.z-dn.net/?f=s%284%29%3D80m)
The speed can now be calculated by substituting t=4 and distance 80 meters to obtain;
![Speed=\frac{80}{4} =20ms^{-1}](https://tex.z-dn.net/?f=Speed%3D%5Cfrac%7B80%7D%7B4%7D%20%3D20ms%5E%7B-1%7D)
Answer:
Side length of each placement is 6 inches.
Step-by-step explanation:
Kelly is using a ribbon to trim two identical placements of length = 80 inches
Each placement is in the shape of a regular hexagon.
So perimeter of these regular hexagons = 2×(Sum of all 6 sides of a hexagon)
Let the side length of each regular hexagon = x inches
Total perimeter of these identical placements = 2(6x) = 12x
Perimeter of identical placements = Length of the ribbon used
12x = (80 - length of leftover ribbon)
12x = 80 - 8
x =
x = 6 inches
Therefore, side length of each placement is 6 inches.