What is the value of z in the equation 4×2-z=7?

Mathematics

1 answer:

sladkih [1.3K]3 years ago

3 0

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Zoey needs at least $30 to buy a gift. She has $12. Which inequality could Zoey use to find out how much more money (m) she need

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The inequality would look something like; x+12=30

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Is (1,-4) a solution to the equation y=-2x?<br> Yes or no? Please help /:

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No it is not, the solution would need to be (2,-4) in order to satisfy the equation y = -2x -- like so -4 = -2(2)

-4 = -4, otherwise the equation won't be satisfied.

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federico ha tomado 2/5 de vaso de leche y maria ,4/10de vaso ¿alguno de los dos ha bebido mas leche o han bebido la misma cantid

umka2103 [35]

Answer:

Han bebido la misma cantidad.

Step-by-step explanation:

De la pregunta,

Frederico = 2/5 vaso de leche

María = 4/10 vaso de leche

Simplificando el gozo de la leche para María

= 2/5

Por tanto, podemos decir que:

Sí, han bebido la misma cantidad.

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3 years ago

There are 48 people who have signed up to attend the midnight barbecue at the Rainbow Canyon Recreation Center. The chef wants t

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A) 264 11/2 *48
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Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

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