Answer:
42°
Step-by-step explanation:
AD bisects ∠CAB, which means it splits ∠CAB into two equal parts. ∠CAB equals 84°. 84° ÷ 2 = 42°.
Answer:
-14c
Step-by-step explanation:
I’m using the actual values 1F = -17C so just times that by 5.4
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:
60 degrees
Step-by-step explanation:
Answer:
y = -(2/3)m - 2
Step-by-step explanation:
recall that the general equation of a straight line in slope-intercept form is
y = mx + b
where, m is the slope and b is the y - intercept
here we are given that the y - intercept is -2, hence the equation becomes:
y = mx + (-2)
or
y = mx -2
we are also given that the x-intercept is -3, which means that when y = 0, x = -3 (simply substitute this into our new equation to solve for m)
0 = m(-3) -2
0 = -3m - 2 (add 3m to both sides)
3m = -2 (divide both sides by 3)
m = -(2/3)
hence our equation is now
y = -(2/3)m - 2
