2 years ago

Evaluate 7+ (-4x²) for x = 0. 1. 0 2. 3 3. 7 3. 23

Mathematics

1 answer:

Flauer [41]2 years ago

6 0

Answer:

substitute

7+( -4×0) = 7 + 0 = 7

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3 years ago

Please Find the distance between the two points rounding to the nearest tenth (if necessary).

Sphinxa [80]

Answer:

10.29 u

Step-by-step explanation:

<u>Given :- </u>

Two points (7,4) and (-2,9) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

$:\implies$ D = √{(x2-x1)² + (y2-y1)²}

$:\implies$ D =√[ (7+2)² +(9-4)²]

$:\implies$ D =√[ 9² +5²]

$:\implies$ D =√[ 81 +25]

$:\implies$ D = 10.29

<h3>Hence the distance between the two points is 10.29 units .</h3>

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3 years ago

Read 2 more answers

Derive this with respect to x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B%281%20%2B%20%20secx%29%20%7D%20" id="Tex

Elenna [48]

$~~~~\dfrac{d}{dx} \left(\dfrac{3}{1 + \sec x} \right)\\\\\\=3 \dfrac{d}{dx} \left( \dfrac 1{ 1+ \sec x} \right)\\\\\\=3 \dfrac{d}{dx} (1+ \sec x)^{-1}\\\\\\=3 (-1) (1 + \sec x )^{-1 -1} \dfrac{d}{dx}( 1 + \sec x)\\\\\\=-3(1 + \sec x)^{-2} ( 0 + \sec x \tan x)\\\\\\=-\dfrac{3\sec x \tan x}{(1 + \sec x)^2}$