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aliina [53]
3 years ago
8

his table gives a record of a marble being rolled along the ground. What was the marble's average speed for this entire trip? 0.

67 m/s 1.5 m/s 1.5 mph 15 m/s

Chemistry
1 answer:
andre [41]3 years ago
8 0

The correct answer is 1.5 m/s

Explanation:

To find the average speed of the movement of a body, for example, the movement of the marble. The first step is to know the total distance traveled and the time of the movement. These two details can be found in the graph presented, in this, the maximum distance (vertical axis) is 15 meters and at this distance, the time is 10 seconds. Now, with this information we can use the formula Average speed = Total distance ÷ Total time.

Average speed = \frac{15 meters}{10 seconds}

Average speed= 1.5 m/s

According to this, the correct answer is 1.5 m/s. Also, meters per second or m/s is the correct unit because the distance is provided in meters (m) and the time is provided in seconds (s).

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Lina20 [59]

Answer:

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7 0
3 years ago
How to set up the rate expressions for the following mechanism?
Anestetic [448]

Answer:

Explanation:

From the given information:

A → B k₁

B → A k₂

B + C → D k₃

The rate law = \dfrac{d[D]}{dt}=k_3[B][C] --- (1)

\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C]

Using steady-state approximation;

\dfrac{d[B]}{dt}=0

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[B] = \dfrac{k_1[A]}{k_2+k_3[C]}

From equation (1), we have:

\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}

when the pressure is high;

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\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \  \text{first order}

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3 0
3 years ago
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