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4 years ago

What’s drugs produce a calming effect by slowing brain activity and reducing the heart rate

Chemistry

1 answer:

asambeis [7]4 years ago

3 0

Answer:

Anti-anxiety

Explanation:

Anti-anxiety drugs, also known as anxiolytics, are drugs that produce a calming effect by slowing brain activity and reducing the heart rate of a person. These drugs are used in order to inhibit anxiety and the symptoms that accompany it, such as tachycardia and palpitations. Although some recreational drugs may induce anxiolysis, in general they tend to be anxiogenic.

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Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.

Elis [28]

Hello :))

Your question was:Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
The answer is: Sublimation

Hope this helps!
Good day! :D

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3 years ago

List of 3 physical properties of tin foil

evablogger [386]

Solid, ductile, and malleable. Ductile means it can conduct heat, and malleable means it can be shaped differently. hope this helps

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4 years ago

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Calculate the equilibrium constant for the following reaction: Co2+ (aq) + Zn(s> CO (s) + Zn2+ (aq)

Simora [160]

<u>Answer:</u> The $K_{eq}$ of the reaction is $1.73\times 10^{16}$

<u>Explanation:</u>

For the given half reactions:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Co^{2+}+2e^-\rightarrow Co(s);E^o_{Co^{2+}/Co}=-0.28V$

Net reaction: $Zn(s)+Co^{2+}\rightarrow Zn^{2+}+Co(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.28-(-0.76)=0.48V$

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

$\Delta G^o=-nfE^o_{cell}$

and,

$\Delta G^o=-RT\ln K_{eq}$

Equating these two equations, we get:

$nfE^o_{cell}=RT\ln K_{eq}$

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

$E^o_{cell}$ = standard electrode potential of the cell = 0.48 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K_{eq}$ = equilibrium constant of the reaction = ?

Putting values in above equation, we get:

$2\times 96500\times 0.48=8.314\times 298\times \ln K_{eq}\\\\K_{eq}=1.73\times 10^{16}$

Hence, the $K_{eq}$ of the reaction is $1.73\times 10^{16}$

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3 years ago

True or false - Evaporating, condensing, melting and freezing are all examples of chemical change.

Fittoniya [83]

False because they can turn back to their original form a chemical change would be like burning paper it can’t be changed back to it’s original offer it’s burnt

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3 years ago

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dimulka [17.4K]

Answer:

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Explanation:

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3 years ago

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