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4 years ago

How would an equation be written for the dissociation of ionic solutes in water?

1 answer:

3 0

1) Assume M refers to a general element and Z referes to other general element.

2) Assume the chemical formula of the ionic compound is MₓZₐ

3) Then the dissociaton would be written:

MₓZₐ → XMᵃ⁺ + AZˣ⁻

That means that the ionic compoud will lead to the X cations Mᵃ⁺ whose oxidation state are a+, and A anions Zˣ⁻ whose oxidation state is x⁻.

5) For example: MgBr₂ (aq) → Mg⁺² (aq) + 2Br⁻ (aq)

6) Explanation: since the water molecules are polar, they will surround (solvate) the three ions that form the compound MgBr₂, overcoming the electrostatic forces that hold together the atoms in the ionic lattice.

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Which of the following correctly lists the name of the element, the symbol for the ion, and the name of the ion?

Yanka [14]

The correct answer is B.

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2 years ago

A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and

Dmitry_Shevchenko [17]

Answer:

1. $Rate =k [NO]^{2}[Cl_{2}]$

2. $k= 0.42 \frac{L^{2}}{mol^{2}*s}$

Explanation:

$Rate =k [NO]^{m}[Cl_{2}]^{n}$

$Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2$

$Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1$

$Rate =k [NO]^{2}[Cl_{2}]^{1}$

$Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12} = 0.42 \frac{L^{2}}{mol^{2}*s}$

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3 years ago

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3 years ago

Lewis structure for 2O2

Mrrafil [7]

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3 years ago

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