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4 years ago

How would an equation be written for the dissociation of ionic solutes in water?

1 answer:

3 0

1) Assume M refers to a general element and Z referes to other general element.

2) Assume the chemical formula of the ionic compound is MₓZₐ

3) Then the dissociaton would be written:

MₓZₐ → XMᵃ⁺ + AZˣ⁻

That means that the ionic compoud will lead to the X cations Mᵃ⁺ whose oxidation state are a+, and A anions Zˣ⁻ whose oxidation state is x⁻.

5) For example: MgBr₂ (aq) → Mg⁺² (aq) + 2Br⁻ (aq)

6) Explanation: since the water molecules are polar, they will surround (solvate) the three ions that form the compound MgBr₂, overcoming the electrostatic forces that hold together the atoms in the ionic lattice.

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If sea water has a density of 1.025 kg/L and 3.5% of the mass in sea water is salt, determine the mass of salt dissolved in 500

Alja [10]

68 kg. There are 58 kg salt in 500 gal seawater.

Step 1. Convert gallons to litres

1 US gal = 3.79 L (1 Imp gal = 4.55 L)

Step 2. Find the volume of the seawater

Volume = 500 gal × (3.79 L/1 gal) = 1895 L

Step 3. Find the mass of the seawater

Mass = 1895 L × (1.025 kg/1 L) = 1942 kg

Step 4. Find the mass of the salt

Mass of salt = 1942 kg seawater × (3.5 kg salt/100 kg seawater) = 68 kg salt

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4 years ago

A cyclinder has a volume of 703 cm3 and a height of 18.5 cm. What can be concluded about the cyclinder

Sergio039 [100]

The volume of a cylinder's formula can be used to find the area of the base.

The formula - r2 h, where r is the cylinder's radius and h is its height, determines the volume of a cylinder.

The density of a cylinder is determined by its volume, which represents how much material may be immersed in it or carried inside of it. The formula r2h, where r is the radius of the circular base and h is the height of the cylinder, determines the volume of a cylinder. Any substance that can fill the cylinder consistently with liquid or another material may be used as the material.

The ratio of the base area to the height can be used to calculate the volume of a cylinder

To learn more about the volume of a cylinder please visit -brainly.com/question/12554533
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7 0

2 years ago

What does the atomic mass describe?

harkovskaia [24]

B., the mass of the nucleus of the atom.
Both the protons and the neutrons are inside the nucleus. The atomic number of an atom is the number of protons, and if you subtract the atomic number from the atomic mass you can find the number of neutrons an atom has.
So, the mass of the protons plus the mass of the neutrons, which are both inside the nucleus, equals the atomic mass.

5 0

3 years ago

Which example is the site of oxidation when the dry cell is operating?

geniusboy [140]

Answer:

solid zinc layer

Explanation:

I took the test :)

6 0

3 years ago

Consider the balanced equation for the following reaction:

Zanzabum

Answer: The amount of carbon dioxide formed in the reaction is 5.663 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8g}{32g/mol}=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $\frac{4}{7}\times 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.143mol\times 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}\times 100\\\\\text{Experimental yield of carbon dioxide}=\frac{90\times 6.292}{100}=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

7 0

3 years ago