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Gnom [1K]
3 years ago
14

What volume would 4.5 moles of helium gas occupy at STP?

Chemistry
1 answer:
zzz [600]3 years ago
7 0

Answer:

100.8 dm3

Explanation:

mol= volume      

       _______

       molar volume  

Simply transpose the formula      

volume=mol x molar volume  

           4.5molx22.4 mol/dm3

=   100.8dm3

NB  STP=22.4 dm3  or 22400 cm3

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Which compound is soluble in water PbS BaS Na2S Fe2S3
Dmitry [639]

Answer:

The answer to your question is Na₂S, if you need to choices the other one is BaS

Explanation:

As a general rule, all the compounds that have sulfur, are insoluble in water, but the are some exceptions.

-Molecules with ammonia

-If the molecule has alkali metals is soluble

-If the molecule has Ca⁺², Sr⁺² and Ba⁺² is soluble in water.

From the compounds given, following the rules, the compound that is soluble in is Na₂S and perhaps BaS.

5 0
3 years ago
10 POINTS
Snowcat [4.5K]
E=hc/λ =6.626×10^-34×3 ×10^8 / 3×10^7 × 10^-9 = 6.626×10 ^-24J.
7 0
3 years ago
What is the enthalpy of reaction from the following energy diagram?
ozzi

A. -20kj

Explanation:

The reaction is exothermic

therefore enthalpy = 20 - 40 = -20

7 0
3 years ago
Read 2 more answers
Each of the chemically active Period 2 elements forms stable compounds in which it has bonds to fluorine.(a) What are the names
Softa [21]

The names of the compound are lithium fluoride ( LiF) , beryllium difluoride (BeF2) , Boron trifluoride (BF3) , carbon tetrafluoride (CF4) , nitrogen trifluoride (NF3) , oxygen difluoride (OF2) .

Lithium is the first element of period 2 which reacts with fluorine to form LiF ( lithium fluoride ) . it is an inorganic compound . it is also a colorless solid . it is less soluble in water . it is chemically stable because of its comparable molecular mass .

Beryllium is the second element of period 2 which reacts with fluorine to give beryllium difluoride (BeF2) . it is inorganic compound . it is highly soluble in water. it is also a stable compound . it have low melting point .

Boron is the third element of period 2 which reacts with fluorine to form

BF3 (Boron trifluoride ) . it is a inorganic compound . it is colorless and toxic gas forms  . it is stable in dry atmosphere but its octet is not satisfied .

Carbon is the 4th element of the period 2 which reacts with fluorine to form carbon tetrafluoride (CF4) . it is not soluble in water . it is a greenhouse gas . it dissolves in oil. it is very stable compound .it forms covalent bond .

Nitrogen is the 5th element of period 2 which reacts with fluorine to form nitrogen trifluoride (NF3) . it is also a inorganic compound . it  is colorless and non-flammable .  it is a stable gas at room temperature .

Oxygen is the 6th element of period 2 which reacts with fluorine to form oxygen difluoride (OF2) . it is colorless poisonous gas . it is partially stable or relatively stable .

Neon is a noble gas and also a stable element . it is odorless and colorless . so it is nonreactive . so it doesn't form bond with fluorine .

<h3>Learn more about Fluorine here :</h3>

brainly.com/question/3494441

#SPJ4

8 0
2 years ago
how would the rate of diffusion change if the po2 in the capillaries was 40 mmhg and the po2 in the muscle cell changed from 40
BlackZzzverrR [31]

The rate of diffusion change would increase if the PO₂ in the capillaries was 40 mmHg and the PO₂ in the muscle cell changed from 40 to 20 mmHg.

Simple diffusion is the movement of molecular substances from a region of higher concentration to lower concentration. The mechanism with which the movement of O₂ travels from the blood to the body tissues takes place with the use of simple diffusion.

Now, if PO₂ changes from 40 → 20 mmHg in the muscle cells, and the PO₂ in the blood = 40mmHg. It implies that the pressure gradient(P) has increased. As such, there is an increase in the rate of diffusion of oxygen from the blood to muscle cells.

Learn more about diffusion here:

brainly.com/question/14392880?referrer=searchResults

6 0
2 years ago
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