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3 years ago

Find the mass of 3.50x10^23 molecules of nitrogen gas

Chemistry

1 answer:

Zarrin [17]3 years ago

4 0

Answer:

16.27 g.

Explanation:

It is known that every 1.0 mol of a compound contains Avogadro's no. of molecules (6.022 x 10²³).

Using cross multiplication:

1.0 mol of N₂ gas contains → 6.022 x 10²³ molecules.

??? mol of N₂ gas contains → 3.50 x 10²³ molecules.

∴ The no. of moles of N₂ gas = (1.0 mol)(3.50 x 10²³ molecules)/(6.022 x 10²³ molecules) = 0.5812 mol.

∴ The mass of 3.50 x 10²³ molecules of N₂ gas = (no. of moles)*(molar mass) = (0.5812 mol)(28.0 g/mol) = 16.27 g.

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Answer:

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Answer:

STEP I

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____________________________

$\\$

$\mathfrak{\underline{\green{ Why\: KOH \:has\: been\: taken\: as\: aqueous ?}}}$

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