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Veseljchak [2.6K]
3 years ago
5

Which two formulas contain 4 atoms of hydrogen?

Chemistry
1 answer:
Rzqust [24]3 years ago
8 0

Methane (CH4) = 1 carbon atom, 4 hydrogen

Sulphuric Acid (H2SO4) = 2 hydrogen atoms, 1 sulfur and 4 oxygen.

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When iron reacts with oxygen, it forms iron oxide, or rust.
Feliz [49]

Answer:

Mass of iron oxide: 79.85 g  

Explanation:

Given data:

Mass of iron = 112 g

Mass of O₂ = 24 g

Mass of iron oxide formed = ?

Solution:

4Fe + 3O₂         →       2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/ molar mass

Number of moles = 112 g/ 55.85 g/mol

Number of moles =  2 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 24 g/ 32 g/mol

Number of moles =  0.75 mol

Now we will compare the moles of oxygen and iron with iron oxide.

                 Fe           :             Fe₂O₃

                 4             :                2

                 2             :                2/4×2 =  1

                O₂            :             Fe₂O₃

                 3             :                2

                 0.75       :                2/3×0.75 =  0.5

The number of moles of iron oxide formed by oxygen are less thus it will be limiting reactant.

Mass of iron oxide:

Mass = number of moles × molar mass

Mass = 0.5 mol  × 159.69 g/mol

Mass = 79.85 g  

3 0
3 years ago
What is an example of the third law of thermodynamics?
Vladimir79 [104]

Answer:S = k × ln(Y)

In this equation, Y is the number of microstates in the system (or the number of ways the system can be ordered), k is the Boltzmann constant (which is found by dividing the ideal gas constant by Avogadro's constant: 1.380649 × 10−23 J/K) and ln is the natural logarithm (a logarithm to the base e).

Explanation:

4 0
3 years ago
How many grams of CO2 are used when 6.50 g of O2 are produced?
RoseWind [281]

Answer:

Approximately 5.05 g of CO2 are used when 6.50 g of O2 are produced.

Explanation:

The answer to this question is the implication that the production of 6.5g of O2 requires 5g-6g CO2, since it is 63% oxygen by mass and 37% carbon dioxide by mass (not including water vapor). This would mean that 4g-5g CO2 productions could be expected to yield 2.25 or so grams oxygen for each gram CO2 produced, depending on how low the temperature was at which the reaction took place (a product like dry ice produces only cold enough to use 1/16th its volume in volume rather than 1/200th).

7 0
3 years ago
Which of the following phrases best defines the word software?
user100 [1]

Answer:

D. a program on a computer

Explanation:

4 0
2 years ago
Read 2 more answers
In an experiment, a solution required 30. 05 g of nacl, 50. 0 g of , and 0. 4006 g of mgso4. Using the correct number of signifi
Radda [10]

When the use of significant figures and rounding up is applied correctly the mass of the mixture will be 80.5 g.

In cases of addition or subtraction, only the last significant figure of every number is taken into account.

In 30.05, this is 5, in the hundredths. When we look at 50.0, the last significant figure is 0, and it is in the tenths. And in 0.4006, the last significant figure is 6, in the ten thousandths. Of these three, the 0 from 50.0 is in the leftmost position, which means that the last significant figure of the result needs to be in the same position (in the tenths).

Moving onto the actual algebraic operation:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

As we established, the last significant figure should be in the tenths, and we will have to round up 4 to 5 (trailing numbers are greater than 0), which means that the resulting mass will be 80.5 g.

You can learn more about significant figures here:

brainly.com/question/14804345

#SPJ4

7 0
2 years ago
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