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sesenic [268]
3 years ago
10

Show that the curve x = 7 cos(t), y = 5 sin(t) cos(t) has two tangents at (0, 0) and find their equations.

Mathematics
1 answer:
elena-s [515]3 years ago
8 0
Y= 5 y =7 thats the smaller slip and larger
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The ratio of the sides of 2 cubes is 2 to 7. If the volume of the smaller cube is 32 u3, then the volume of the larger cube is _
satela [25.4K]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{2}{7}=\cfrac{\sqrt[3]{32}}{\sqrt[3]{v}}\implies \cfrac{2}{7}=\sqrt[3]{\cfrac{32}{v}}\implies \left( \cfrac{2}{7} \right)^3=\cfrac{32}{v}
\\\\\\
\cfrac{2^3}{7^3}=\cfrac{32}{v}\implies v=\cfrac{7^3\cdot 32}{2^3}
5 0
3 years ago
right triangle ABC is shown below. A similar right triangle would be created by a run of 4 and rise of______
Svetllana [295]

The rise would have to be 12.

This is because in order to be "Similar" triangles the sides need to be proportionate.

(1/3 = 4/12)

4 0
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Write 1.67% as a decimal. thx :)
Bas_tet [7]

Answer:

0.0167

Step-by-step explanation:

divide by 100

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I need help !!!!!!!!!!
sergiy2304 [10]
You need to multiply lxh and that is 32 
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