Answer:
See Below.
Step-by-step explanation:
We want to show that the function:
Increases for all values of <em>x</em>.
A function is increasing whenever its derivative is positive.
So, find the derivative of our function:
![\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5Be%5Ex%20-%20e%5E%7B-x%7D%5Cright%5D)
Differentiate:
Simplify:
Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
Answer: 73
Step-by-step explanation:
Multiply using the FOIL method, then combine the real and imaginary parts of the expression.
73
Here 5 - 4/9
multiply 9 and divide 9 to 5. It gives 45/9.
Hence, above fraction becomes,
45/9 - 4/9 = (45 - 4) / 9 = 41 / 9
Hope it helps.
