The half-life of a second-order reaction is
Further explanation:
Second-order reaction:
A reaction is said to be of second-order if its rate is proportional to the square of the concentration of one reactant. The general example of second-order reaction is,
Here,
A is the reactant.
P is the product.
The rate is calculated by using the following equation:
Another form of second-order reaction is as follows:
Here,
A and B are the two different reactants.
P is the product.
The rate is calculated by using the following equation:
Half-life:
Half-life is defined as the time required to reduce the concentration of reactant to half of its initial value. It is denoted by . The general expression to calculate of second-order reaction is,
…… (1)
Here,
is the half-life of the reaction.
k is the rate constant for the reaction.
is the initial concentration of the reactant.
The rate constant for the given reaction is .
The initial concentration of the given reaction is 0.30 M.
Substitute these values in equation (1).
So, the half-life of a second-order reaction is 6.173 seconds.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Chemical Kinetics
Keywords: second-order reaction, half-life, initial, half, 6.173 seconds, 0.30 m, k, A0, A, B, P, 2A, reactant, product, t1/2.