1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikklg [1K]
3 years ago
5

Measurements are commonly recorded as

Chemistry
1 answer:
kaheart [24]3 years ago
5 0

Kilometers, Meters and centimeters if metric

Feet, inches, yards and miles if customary ( u.s.)

You might be interested in
Give the major force between acetone and chloroform.
EleoNora [17]
Says here the answer is <span>dipole-dipole</span>
4 0
3 years ago
How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?
zlopas [31]
<h3>Answer:</h3>

1.83 × 10⁻⁷ mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.60 × 10⁻⁵ g Au (Gold)

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. Multiply:                            \displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

4 0
3 years ago
A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature
Doss [256]

Answer:

d i took the test

Explanation:

5 0
3 years ago
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
Identify the compound that has the same structure as sodium chloride. identify the compound that has the same structure as sodiu
olga_2 [115]
Sodium chloride is an ionic compound. ionic compound is when the compound itself is made up of a metal and non-metal element.
thus the answer is potassium bromide and cesium chloride.
8 0
3 years ago
Read 2 more answers
Other questions:
  • [04.02]What coefficients must be added to balance the following equation?
    5·1 answer
  • Which diagram best illustrates the stage in the formation of the solar system at which the sun formed?​
    13·1 answer
  • An ideal gas cannot exist outside of ideal gas conditions<br><br> true or false ?
    7·1 answer
  • An ice freezer behind a restaurant has a freon leak, releasing 41.60 g of C2H2F3Cl into the air every week. If the leak is not f
    14·1 answer
  • Once two gas particles undergo an elastic collision, the particles
    5·1 answer
  • “Jesus came to serve. How is He calling me to serve?”
    8·1 answer
  • Scientists carried out an experiment with flowers from plant X and found out that within three minutes of exposure to the sound
    14·1 answer
  • Which property is NOT used to separate a mixture?
    12·1 answer
  • Complete the following sentence: "During a chemical reaction."
    11·1 answer
  • Given the reaction:
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!