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user100 [1]
3 years ago
13

The bulb lights up in the circuit. Only two rods are conductors of electricity. Which one of the rods, X, Y or Z is definitely a

conductor of electricity? Explain why.​

Chemistry
1 answer:
meriva3 years ago
4 0

Answer: Rod X.

Explanation:

Ok, the electricity starts in the top left part. First, it must travel in the X rod, then it keeps traveling until it reaches the parallel path, and it can go to the Z rod, to the Y rod, or to both of them, and then it reaches the bulb (the circle with a X inside of it).

We know that two rods are conductors of electricity.

Now, suppose the case where rods Z and Y are the ones that conduct electricity, this means that X does not conduct electricity, then when the current reaches to X it stops (because X does not conduct) then the electricity never reaches the rods Z and Y, and then the electricity never reaches the bulb, but we know that the bulb lights up, so we must have that X is one of the conducting rods.

Then, if for example, Y does not conduct electricity, the electricity still can run through the Z rod and eventually reach the bulb.

So we can conclude that the rod that is definitely a conductor of electricity is rod X

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How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?
weeeeeb [17]

Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

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Now put all the given values in this formula, we get:

0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

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7 0
3 years ago
If the specific heat of a solution is 4.18 J/goC, and you have 296 mL (1.03 g/mL) which increases in temperature by 6.9 degrees,
Sergeu [11.5K]

Answer:

Q = 8.8 kJ

Explanation:

Step 1: Data given

The specific heat of a solution = 4.18 J/g°C

Volume = 296 mL

Density = 1.03 g/mL

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Step 2: Calculate the mass of the solution

mass = density * volume

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Step 3: Calculate the heat

Q = m*c*ΔT

⇒ with Q = the heat in Joules = TO BE DETERMINED

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⇒ with ΔT = the change in temperature = 6.9 °C

Q = 304.88 g * 4.18 J/g°c * 6.9 °C

Q = 8793.3 J = 8.8 kJ

Q = 8.8 kJ

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