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3 years ago

Nucleotides have a phosphate group attached at the ___ carbon atom of the sugar.

Chemistry

1 answer:

Tanzania [10]3 years ago

6 0

Answer:

Nucleotides have a phosphate group attached at the 5' carbon atom of the sugar.

Explanation:

Phosphate group is attached to the sugar molecule in the place of -OH.

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How does ppm compare to ppb?

hodyreva [135]

<span>An even smaller concentration measurement is parts per billion (ppb). One ppb is one part in 1 billion. One drop of ink in one of the largest tanker trucks used to haul gasoline would be an ink concentration of 1 ppb. It is important to know the difference between ppm and ppb. I hope this helped :)</span>

4 0

4 years ago

g Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3 , at 500 K: PCl3 (g) + Cl2 (g) PCl5 (g) If the

Ksivusya [100]

Answer:

C. Remains the same

A. Is greater than Kc

B. Run in the reverse direction to restablish equilibrium.

C. Remain the same

Explanation:

As the reaction is exothermic (ΔH < 0), when occurs, produce heat.

Based on Le Chatelier's principle, if the temperature decreases, <em>the system will produce more product trying to restore the equilibrium</em>

* The value of Kc doesn't change because is the constant of the reaction, Kc. That is,

<h3>C. Remains the same</h3>

* Qc is the ratio between products and reactants. As more product is produced, Qc will increase becomes:

<h3>A. Is greater than Kc</h3>

*After the formation of product, the system must:

<h3>B. Run in the reverse direction to restablish equilibrium. </h3>

Because product is produced

*Cl₂ as reactant is consumed producing more product, decreasing its concentration. But when the equilibrium is restored, its concentration would be the same

<h3>C. Remain the same</h3>

3 0

3 years ago

How would an equation be written for the dissociation of ionic solutes in water?

tangare [24]

1) Assume M refers to a general element and Z referes to other general element.

2) Assume the chemical formula of the ionic compound is MₓZₐ

3) Then the dissociaton would be written:

MₓZₐ → XMᵃ⁺ + AZˣ⁻

That means that the ionic compoud will lead to the X cations Mᵃ⁺ whose oxidation state are a+, and A anions Zˣ⁻ whose oxidation state is x⁻.

5) For example: MgBr₂ (aq) → Mg⁺² (aq) + 2Br⁻ (aq)

6) Explanation: since the water molecules are polar, they will surround (solvate) the three ions that form the compound MgBr₂, overcoming the electrostatic forces that hold together the atoms in the ionic lattice.

3 0

4 years ago

How many liters of oxygen gas, at standard

Karo-lina-s [1.5K]

Answer:

Explanation:

For the balanced reaction:

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

5 0

4 years ago

A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch

Dahasolnce [82]

Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

$HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)$

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

$250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})$

= 0.075 mol HCl

$100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})$

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = $\frac{0.050mol}{0.350L}$

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

6 0

4 years ago