Choose all that correctly describe the pattern of association between the two quantities on the scatter plots.

Mathematics

2 answers:

Likurg_2 [28]2 years ago

6 0

Positive and negative

Dovator [93]2 years ago

6 0

The top two are wrong because they are going the wrong way if I remember correctly. The bottom two should be right.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B12x%7D%7B2x-3x-10%7D%20-%20%5Cfrac%7Bx%7D%7B%28x-5%29%7D" id="TexFormula1" title="\f

uysha [10]

Answer:

Step-by-step explanation:

$\frac{12x}{2x-3x-10}-\frac{x}{x-5}=\frac{12x}{-x-10}-\frac{x}{x-5}\\\\=\frac{12x}{-(x+10)}-\frac{x}{x-5}\\\\=\frac{-12x}{x+10}-\frac{x}{x-5}\\\\=\frac{-12x*(x-5)}{(x+10)*(x-5)}-\frac{x*(x+10)}{(x-5(x+10)}\\\\=\frac{-12x*x-5*(-12x)}{(x+10)(x-5)}-\frac{x*x+x*10}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x}{(x+10)(x-5)}-\frac{x^{2}+10x}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x-(x^{2}+10x)}{(x+10)(x-5)}\\\\=\frac{-12x^{2} + 60x - x^{2}-10x}{x^{2}+5x-50}\\\\=\frac{-13x^{2}+50x}{x^{2}+5x-50}$

8 0

2 years ago

Read 2 more answers

Someone HELP (sorry if the picture is poor quality)

adoni [48]

Not sure but i would go bottom left corner answer

4 0

2 years ago

In a sample of 57 temperature readings taken from the freezer of a restaurant, the mean is 29.6 degrees and the population stand

Natalka [10]

Answer:

(29.14 ; 30.06)

Step-by-step explanation:

Given that'

Sample size (n) = 57

Mean (m) = 29.6

Population standard deviation (σ) = 2.7

Confidence interval = 80%

= (1 - 0.8) / 2 = 0.1

Mean ± z * σ/√n

Using the Z probability calculator : Z0. 1 = 1.28

Hence,

29.6 ± 1.28 * (2.7 / √57)

29.6 - (1.28 * 0.3576237) ; 29.6 + (1.28 * 0.3576237)

29.142241664 ; 30.057758336

(29.14 ; 30.06)

8 0

2 years ago

I need help! please!

mamaluj [8]

Answer:

$- \frac{1}{3}$

Step-by-step explanation:

The only thing important in this question in the original equation is the slope, which is 3, the multiplyer for x. To find the opposite slope follow the steps below.

The first step is to make the original slope into a fraction.

$\frac{3}{1}$