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3 years ago

1. Most credit card incentive programs give----

1 answer:

3 0

1. Most credit card incentive programs give
b. cashback
2. To calculate a rewards program incentive, you---
b. use the percentage number
3. For this we need to solve:
The cashback is 2% and the purchase amount is $1685.90. We just multiply the percentage to the purchase amount to know what is the 2% of 1685.90.

Solution:
*remember to change the percent to its decimal form by moving the percent two places to the left. 2%=.02

1685.90*.02=33.718 or 33.72

Answer: a

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What is the value of x?

ikadub [295]

Answer:

x = 22

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the interior angles

6x+1 = 79+ 2x+10

Combine like terms

6x+1 = 2x+89

Subtract 2x from each side

4x+1 = 89

Subtract 1 from each side

4x = 88

Divide by 4

4x/4 = 88/4

x = 22

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3 years ago

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#2 what number is 75% of 300? A) 36 B) 22.5 C) 2250 D) 225

Dmitry_Shevchenko [17]

The answer would be D) 225, because 0.75 x 300 = 225.

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4 years ago

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N is the set of whole numbers that are factors of 12. N=???????

Aleks04 [339]

Answer:

is the set of real numbers that are factors of 12. {1, 2, 3, 4, 6}

Step-by-step explanation:

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4 years ago

The National Center for Education Statistics reported that 47% of college students work to pay for tuition and livingexpenses. A

8090 [49]

Answer:

a) The 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses is (0.4239, 0.5161).

b) The 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses is (0.4094, 0.5306).

c)The margin of error increases as the confidence level increases.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 450, p = 0.47$

a) Provide a 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses.

95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47*0.53}{450}} = 0.4239$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 1.96\sqrt{\frac{0.47*0.53}{450}}{119}} = 0.5161$

The 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses is (0.4239, 0.5161).

b. Provide a 99% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses.

95% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 2.575\sqrt{\frac{0.47*0.53}{450}} = 0.4094$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 2.575\sqrt{\frac{0.47*0.53}{450}}{119}} = 0.5306$

The 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses is (0.4094, 0.5306).

c What happens to the margin of error as the conﬁdence is increased from 95% to 99%?

The margin of error is the subtraction of the upper end by the lower end of the interval, divided by 2. So

95% confidence interval

$M = \frac{(0.5161 - 0.4239)}{2} = 0.0461$

99% confidence interval

$M = \frac{(0.5306 - 0.4094)}{2} = 0.0606$

The margin of error increases as the confidence level increases.

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3 years ago

Can someone please help me Please I'm desperate

Yuri [45]

Answer:

James is 37, Rob is 44, and Kate is 35

Step-by-step explanation:

Set up an equation where x is James' age:

Rob's age can be represented by x + 7, since he is 7 years older than James

Kate's age can be represented by x - 2, since she is 2 years younger than James

Add these together in the equation and set it equal to 116:

(x + 7) + (x - 2) + (x) = 116

Add like terms and solve for x:

(x + 7) + (x - 2) + (x) = 116

3x + 5 = 116

3x = 111

x = 37

So, James is 37.

Find Rob's age by adding 7 to this:

37 + 7

= 44

Find Kate's age by subtracting 2:

37 - 2

= 35

So, James is 37, Rob is 44, and Kate is 35

4 0

3 years ago

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