1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zigmanuir [339]
3 years ago
15

What is the coefficient of silver in the final, balanced equation for this reaction?

Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer: 3

Explanation:

An oxide-reduction reaction or, simply, redox reaction, is a <u>chemical reaction in which one or more electrons are transferred between the reactants</u>, causing a change in their oxidation states, which is the hypothetical electric charge that the atom would have if all its links with different elements were 100% ionic.

For there to be a reduction-oxidation reaction, in the system there must be an element that yields electrons and another that accepts them:

  • The oxidizing agent picks up electrons and remains with a state of oxidation inferior to that which it had, that is, it is reduced.
  • The reducing agent supplies electrons from its chemical structure to the medium, increasing its oxidation state, ie, being oxidized.

To balance a redox equation you must <u>identify the elements that are oxidized and reduced and the amount of electrons that they release or capture, respectively. </u>

In the reaction that arises in the question the silver (Ag) is reduced <u>because it decreases its oxidation state from +1 to 0</u> and the aluminum (Al) is oxidized because <u>its oxidation state increases from 0 to +3</u>, releasing 3 electrons (e⁻). Then we can raise two half-reactions:

Ag⁺ + e⁻ → Ag⁰

Al⁰ → Al⁺³ + 3e⁻

In order to obtain the balanced equation, we must multiply the first half-reaction by 3 so that, when both half-reactions are added, the electrons are canceled. In this way:

(Ag⁺ + e⁻ → Ag⁰ ) x3

Al⁰ → Al⁺³ + 3e⁻               +

-------------------------------------

3Ag⁺ + Al⁰ → 3Ag⁰ + Al⁺³

So, the coefficient of silver in the final balanced equation is 3.

You might be interested in
Which has the largest atomic size selenium or oxygen?
kolbaska11 [484]

Answer:

Selenium

Explanation:

selenium has 4 energy levels (think a 4 story building) while oxygen only has 2 (think 2 story building). which one is taller?

3 0
3 years ago
For neon, determine the moles and mass contained in a 29.9−L volume at a pressure of 481.1 torr at a temperature of 300.0 K.
kondor19780726 [428]

Answer:

.7689 mol

15.516 g

Explanation:

Use the Ideal Gas Law, PV = nRT.

Make sure to use the correct ideal gas constant R. You can either put R in torr, or you can change the pressure to atm. I've just used the torr ideal gas constant.

481.1 torr * 29.9 L = n 62.364 LTorr/molK * 300 K

14384.89 = 18709.2n

n = <u>.7689 mol</u>

The molar mass of neon (remember that neon gas = Ne, it's not diatomic) is 20.18 g/mol from the periodic table.

.7689 mol * 20.18 g/mol = <u>15.516 g</u>

8 0
3 years ago
A gate made of painted iron is beginning to rest in areas where the paint has worn away why is the formation of rust considered
Pavel [41]

Answer:

because it is two substances reacting together to create a new substance

Explanation:

when iron rusts, iron molecules react with the oxygen molecules creating iron oxide aka rust.

3 0
2 years ago
A high ph value indicates:
mote1985 [20]
... indicates that it also has a high concentration of Hydroxide (OH) and that it is more basic.
8 0
2 years ago
The normal freezing point of a certain liquid Xis-7.30°C but when l02. g of iron(III) chloride (FeCl3) are dissolved in 650. g o
IRISSAK [1]

Answer:

2.7 °C.kg/mol

Explanation:

Step 1: Calculate the freezing point depression (ΔT)

The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:

ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C

Step 2: Calculate the molality of the solution (b)

We will use the following expression.

b = mass of solute / molar mass of solute × kilograms of solvent

b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg

Step 3: Calculate the molal freezing point depression constant Kf of X

Freezing point depression is a colligative property. It can be calculated using the following expression.

ΔT = Kf × b

Kf = ΔT / b

Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol

7 0
2 years ago
Other questions:
  • What is 3623÷72×2(59)1(4)&lt;8335×(3)(2x)
    5·1 answer
  • In the "Design a Thermos" lab, the temperature of the thermos was compared with a container that was not insulated.
    7·2 answers
  • How might proper lab techniques impact a scientist work?
    14·1 answer
  • Calculate the number of atoms in a 7.45x10^3 g sample of sodium
    12·1 answer
  • Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×
    8·1 answer
  • An ordered list of chemical substances is shown.
    5·1 answer
  • PLEASE HURRY IM TIMED Which of the following are examples of physical changes? (Select all that apply.)
    15·1 answer
  • During an experiment, distilled water was placed in a sealed container and the container was heated gradually. Describe this sys
    11·1 answer
  • Chemical bonding explaining ​
    11·1 answer
  • If a buffer solution is 0.130 M in a weak acid (K_a = 1.7 x 10^-5) and 0.590 M in its conjugate base, what is the pH?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!