Physical or chemical ?

The correct answer among the choices given is the last option. Galaxies are classified according to their shapes or visual morphology. There three main types of galaxies currently. They are the elliptical, spiral and irregular. Elliptical galaxies are like a spheriod or an elongated sphere. Spiral galaxies are characterized and distinguished by having a bulge, a disk and a halo. Lastly, irregular galaxies do not have regular or symmetrical shape.

3 0

3 years ago

The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia: 2N0(g) +02(g) 2NO2 (g) The

Tresset [83]

The question is incomplete, complete question is :

The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia:

Step 1 : $4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)$

Step 2 : $2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)$

The net reaction is:

$4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)$

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1$ and $K_2$ . If you need to include any physical constants, be sure you use their standard symbols

Answer:

Equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1 \& K_2$ :

$K=K_1\time (K_2)^2$

Explanation:

Step 1 : $4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)$

Expression of an equilibrium constant can be written as:

$K_1=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^5}$

Step 2 : $2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)$

Expression of an equilibrium constant can be written as:

$K_2=\frac{[NO_2]^2}{[NO]^2[O_2]}$

The net reaction is:

$4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)$

Expression of an equilibrium constant can be written as:

$K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}$

Multiply and divide $[NO]^4$ ;

$K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO]^4}{[NO]^4}$

$K=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO_2]^4}{[NO]^4}$

$K=K_1\times \frac{[NO_2]^4}{[O_2]^2[NO]^4}$

$K=K_1\times (\frac{[NO_2]^2}{[O_2]^1[NO]^2})^2$

$K=K_1\time (K_2)^2$

So , the equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1 \& K_2$ :

$K=K_1\time (K_2)^2$

4 0

3 years ago

A chef in restaurant baking 2 different desserts in the oven . He removes a pumpkin and some chocolate chip cookies at the same

valentina_108 [34]

Answer:

the air molecules from the cookies diffused faster than the air molecules from the pumpkin

Explanation:

The smell of cookies reaches first because the air molecules from the cookies were able to diffuse faster than the air molecules from the pumpkin.

<em>At constant temperature, the diffusion rates of two molecules would be dependent on the size of the molecules. The bigger the size of the molecule, the more time it will take for the molecule to diffuse and vice versa. </em>

Thus, <u>since the pumpkin and the cookies were baked at the same temperature, the smell of the cookies was perceived first because the air molecules of the cookies are smaller in size than the air molecules of the pumpkin.</u>

5 0

3 years ago

Why do commercial airliners encounter very little turbulence above 25,000 feet?

Nesterboy [21]

Answer:

Water vapor has mostly disappeared at colder elevations and its effect on weather turbulence.

Explanation:

3 0

3 years ago